<span>The answers to this problem are:<span>(<span>±5</span></span>√3/8,±5/8)<span>Here is the solution:
Step 1: <span><span><span>x2</span>+<span>y2</span>=<span>2516</span>[2]</span><span><span>x2</span>+<span>y2</span>=<span>2516</span>[2]</span></span>
Step 2: Substitute:<span>
</span><span><span>8<span><span>(<span>25/16</span>)^</span>2</span>=25(<span>x^2</span>−<span>y^2</span>)
</span><span>8<span><span>(<span>25/16</span>)^</span>2</span>=25(<span>x^2</span>−<span>y^2</span>)</span></span>
</span><span>x^2</span>−<span>y^2</span>=<span>25/32</span><span>.
Add [2] and [3]:<span>
</span><span>2<span>x^2</span>=<span>75/32
</span><span>x^2</span>=<span>75/74</span></span>
<span>x=±5</span></span>√3/8<span>
Substitute into [2]:<span>
</span><span><span>75/64</span>+<span>y^2</span>=<span>50/32
</span><span>y^2</span>=<span>25/64</span></span>
<span>y=±<span>5/8</span></span>
</span>
</span>
The answer is -6. because 12,10,8,6,4,2,0,-2,-4,-6.
Answer:
you have to sell 6 tables to meet all requirements
Step-by-step explanation:
chairs=$50x
tables=$550x
24 chairs×50= $1200
4100-1200= $2900
take $2900 and divide by $550 to find the exact number of tables which is 5 but selling 5 tables and 24 chairs doesnt reach the $4100 mark so I rounded up to 6 tables which doesnt surpass the maximum number of furniture(32) but beats the $4100 mark
It would take the car 5 hours to travel 300km.
Equation used to solve: (120÷2)×6
Answer: 
.
Step-by-step explanation:
The given function is
Using chain rule differentiate w.r.t. x.
![\left[\because \dfrac{d}{dx}\sin x=\cos x\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Csin%20x%3D%5Ccos%20x%5Cright%5D)
![f'(x)=\cos(9\ln (x))\left[9\dfrac{d}{dx}(\ln (x))\right]](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Ccos%289%5Cln%20%28x%29%29%5Cleft%5B9%5Cdfrac%7Bd%7D%7Bdx%7D%28%5Cln%20%28x%29%29%5Cright%5D)
![f'(x)=\cos(9\ln (x))\left[9\times \dfrac{1}{x}\right]](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Ccos%289%5Cln%20%28x%29%29%5Cleft%5B9%5Ctimes%20%5Cdfrac%7B1%7D%7Bx%7D%5Cright%5D)
![\left[\because \dfrac{d}{dx}\ln x=\dfrac{1}{x}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Cln%20x%3D%5Cdfrac%7B1%7D%7Bx%7D%5Cright%5D)
Therefore, .
