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liraira [26]
3 years ago
13

Latrell bought 4 bags of powdered sugar. He got a total of 5 1/2 cups of sugar. How many cups of sugar were in each bag?

Mathematics
1 answer:
Stels [109]3 years ago
5 0
So all 4 bags of sugar yielded 5 and 1/2 cups..... well.. how many in each one?  well, let's split the 5 and 1/2 evenly in 4 pieces.

\bf \stackrel{mixed}{5}\frac{1}{2}\implies \cfrac{5\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{11}{2}}\\\\
-------------------------------\\\\
\cfrac{\quad\frac{11}{2} \quad }{4}\implies \cfrac{\quad\frac{11}{2} \quad }{\frac{4}{1}}\implies \cfrac{11}{2}\cdot \cfrac{1}{4}\implies \cfrac{11}{8}\implies \stackrel{cups}{1\frac{3}{8}
}
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In this exercise, we are conducting many hypothesis tests to test a claim. Assume that the null hypothesis is true. If 400 tests
Brums [2.3K]

Answer:

Since the null hypothesis is true, finding the significance is a type I error.

The probability of the year I error = level of significance = 0.05.

so, the number of tests that will be incorrectly found significant is computed as follow: 0.05 * 100 = 5

Therefore, 5 tests will be incorrectly found significant given that the null hypothesis is true.

3 0
3 years ago
Can someone plz help me
Illusion [34]
First rectangle:
Has 3 cubes in each 5 layers, and imagine it, so we have all dimension needed which is:
l=3 unit
w=1 unit
h=5 unit.
V=l×w×h
V=3×1×5
V=15 cubic inches.

Second rectangular:
Doing the same like that to get:
l=5 unit
w=1 unit
h=3 unit
V=15 cubic inches. As a result, there are no prism that are greater to each other, which mean that they have the same volume of 15 cubic inches. Hope it help!
6 0
3 years ago
The probability of an event is 3/10 . What are the odds of the same event?
kozerog [31]

Answer:

D. \frac{3}{7}

Step-by-step explanation:

We have been given that the probability of an event is 3/10.  

To find the odds of the same event we will use formula:

\text{Odds of an event}=\frac{\text{Probability of the event}}{\text{1-Probability of the event}}

\text{Odds of the event}=\frac{\frac{3}{10}}{1-\frac{3}{10}}

\text{Odds of the event}=\frac{\frac{3}{10}}{\frac{1*10}{10}-\frac{3}{10}}

\text{Odds of the event}=\frac{\frac{3}{10}}{\frac{10-3}{10}}

\text{Odds of the event}=\frac{\frac{3}{10}}{\frac{7}{10}}

Dividing a fraction with another fraction is same as multiplying the 1st fraction by the reciprocal of second fraction.

\text{Odds of the event}=\frac{3}{10}\times \frac{10}{7}

\text{Odds of the event}=\frac{3}{7}

Therefore, the odds of the same event is \frac{3}{7} and option D is the correct choice.


8 0
3 years ago
Cuantos años hay 5823 días
jonny [76]

Answer:

16 anos

Step-by-step explanation:

6 0
3 years ago
Joshua is 1.45 meters tall. At 2 p.m., he measures the length of a tree's shadow to be 31.65 meters. He stands 26.2 meters away
Lena [83]

Answer:

The height of the tree=8.42 m

Step-by-step explanation:

We are given that

Height of Joshua, h=1.45 m

Length of tree's shadow, L=31.65 m

Distance between tree and Joshua=26.2 m

We have to find the height of the tree.

BC=26.2 m

BD=31.65m

CD=BD-BC

CD=31.65-26.2=5.45 m

EC=1.45 m

All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.

\triangle ABD\sim \triangle ECD

\frac{AB}{EC}=\frac{BD}{CD}

Substitute the values

\frac{AB}{1.45}=\frac{31.65}{5.45}

AB=\frac{31.65\times 1.45}{5.45}

AB=8.42m

Hence, the height of the tree=8.42 m

6 0
3 years ago
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