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Leya [2.2K]
3 years ago
10

An online furniture store sells chairs for $50 each and tables for $550 each. Every day, the store can ship a maximum of 32 piec

es of furniture and must sell no less than $4100 worth of chairs and tables. If 24 chairs were sold, determine the minimum number of tables that the the store must sell in order to meet the requirements. If there are no possible solutions, submit an empty answer.
Mathematics
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:

you have to sell 6 tables to meet all requirements

Step-by-step explanation:

chairs=$50x

tables=$550x

24 chairs×50= $1200

4100-1200= $2900

take $2900 and divide by $550 to find the exact number of tables which is 5 but selling 5 tables and 24 chairs doesnt reach the $4100 mark so I rounded up to 6 tables which doesnt surpass the maximum number of furniture(32) but beats the $4100 mark

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Answer:  -\frac{\sqrt{2a}}{8a}

=======================================================

Explanation:

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\displaystyle \lim_{x\to a} \frac{2a-2x}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2(-a+x)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2(x-a)}{4(x-a)(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\\lim_{x\to a} \frac{-2}{4(\sqrt{3a-x}+\sqrt{x+a})}\\\\\\

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