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3 years ago

Find the area and perimeter of this irregular shape: picture #8

Mathematics

2 answers:

kompoz [17]3 years ago

4 0

Answer:

Peimeter = 14.2 mm

Area = 9.2 sq mm

Step-by-step explanation:

Given figure is a trapezoid.

Perimeter = 6 + 3.6 + 2 + 2.6 mm = 14.2 mm

Area = 1/2 * ( 6 + 2 ) * 2.3 sqmm = 9.2 mm

8090 [49]3 years ago

3 0

Answer:

Perimeter: 14.2

Area: 9.2

Step-by-step explanation:

Simple times for area

simple plus for perimeter

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A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

4 0

3 years ago

Multi-step K is the midpoint of JL, JL=4x-2, and JK=7. Find x, KL, and JL

ddd [48]

If K is midpoint of JL then JK = 0.5JL

JL = 4x - 2; JK = 7

The equation:
0.5(4x - 2) = 7
2x - 1 = 7 |add 1 to both sides
2x = 8 |divide both sides by 2
x = 4

JL = 4(4) - 2 = 16 - 2 = 14

KL = JK = 7

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3 years ago

Which of the following is the solution to the equation 4 / 5n = 20?

S_A_V [24]

N=25 because 20 divided by 4 is 5 which is 1/5 of n meaning 5x5 is 25

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3 years ago

Which of the following is not a characteristic of non-Euclidean geometry? A. Space is saddle-curved. B. The sum of the angles in

kobusy [5.1K]

The correct answer is
A. Space is saddle-curved

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3 years ago

Which of the following statements best describes the effect of replacing the graph of y = f(x) with the graph of y = f(x) + 20

yawa3891 [41]

If you add a constant to the original equation, you are actually shifting up or down

Since the constant is positive, you are shifting the graph 20 units up

5 0

3 years ago

Read 2 more answers