Are you able to ask your teacher?
In y = mx + b form, which is what ur equation is in, the y int can be found in the b position
y = mx + b
y = x + 6
as u can see, the number in the b position, ur y int, is 6 <==
Answer:
The co-ordinates of Q' is (5,2).
Step-by-step explanation:
Given:
Pre-image point
Q(-7,-6)
To find Image point Q' after following translation.
Solution:
Translation rules:
Horizontal shift:
when 
the point is translated 
units to the right.
when 
the point is translated units to the left.
Vertical shift:
when the point is translated units up.
when the point is translated units down.
Given translation shows the point is shifted 12 units to the right and 8 units up.
The point Q' can be given as:
Q'=
So, the co-ordinates of Q' is (5,2). (Answer)
Answer:
4/7
Step-by-step explanation:
Tan= Opposite/Adjacent
Tan<f = 4/7
2. Sorry if I’m wrong but that’s what I just put
