well, if the diameter is 5, thus its radius must be half that, or 2.5, and therefore, the radius of the one four times as much will be (4)(2.5).
Let's simply get their difference, since that'd be how much more is needed from the smaller to larger sphere.
![~\hfill \stackrel{\textit{surface area of a sphere}}{SA=4\pi r^2}\qquad \qquad r=radius~\hfill \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\large difference of their areas}}{\stackrel{\textit{radius of (4)(2.5)}}{4\pi (4)(2.5)^2}~~ - ~~\stackrel{\textit{radius of 2.5}}{4\pi (2.5)^2}}\implies 100\pi -25\pi \implies 75\pi ~~ \approx ~~235.62~ft^2](https://tex.z-dn.net/?f=~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bsurface%20area%20of%20a%20sphere%7D%7D%7BSA%3D4%5Cpi%20r%5E2%7D%5Cqquad%20%5Cqquad%20r%3Dradius~%5Chfill%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20difference%20of%20their%20areas%7D%7D%7B%5Cstackrel%7B%5Ctextit%7Bradius%20of%20%284%29%282.5%29%7D%7D%7B4%5Cpi%20%284%29%282.5%29%5E2%7D~~%20-%20~~%5Cstackrel%7B%5Ctextit%7Bradius%20of%202.5%7D%7D%7B4%5Cpi%20%282.5%29%5E2%7D%7D%5Cimplies%20100%5Cpi%20-25%5Cpi%20%5Cimplies%2075%5Cpi%20~~%20%5Capprox%20~~235.62~ft%5E2)
Answer:
y=-6x-24
Step-by-step explanation:
just expand
y+6=-6x-18
then move the six from the left to the right
y=-6x-24
Set the equations to equal each other because the angles are equal.
8x - 63 = 4x - 27
+63 on both sides
8x = 4x + 36
-4x on both sides
4x = 36
/4 on both sides
x = 9
Answer:
x = 9
m∠B = 31.7° , a = 21.1 ft , b = 13.0 ft
Step-by-step explanation:
If ABC is a right triangle, where the right angle is B, then
- The hypotenuse of the triangle is b and a , c are its legs
- sin(A) =

- sin(C) =


- The sum of the measures of the two acute angles A and C is 90°
∵ ABC is a right triangle
∵ m∠C = 90°
∴ c is the hypotenuse and a , b are its legs
∵ m∠A = 58.3°
- The sum of the two acute angles in the right triangle = 90°
∴ m∠A + m∠B = 90°
- Substitute the measure of angle A
∴ 58.3 + m∠B = 90
- Subtract 58.3 from both sides
∴ m∠B = 31.7°
∵ sin(A) = 
∵ c = 24.8 feet
∴ sin(58.3) = 
- By using cross multiplication
∴ a = (24.8) × sin(58.3)
∴ a = 21.1 ft
∵ sin(B) = 
∵ c = 24.8 feet
∴ sin(31.7) = 
- By using cross multiplication
∴ b = (24.8) × sin(31.7)
∴ b = 13.0 ft
m∠B = 31.7° , a = 21.1 ft , b = 13.0 ft
Learn more:
You can learn more about solving the triangle in brainly.com/question/12985572
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14.18 because you do pi times the radius squared and divide it by 2.