Answer:
B It can seem boring.
Explanation:
The repetition of visual effects results in consistency, rhythm, and movement. However, too much repetition can cause monotony and boredom. And this is not good for you certainly. You are certainly going to lose the audience. And too much harmony in design as well in a similar manner causes boredom, or it can seem boring. And hence, the correct option here is B it can seem boring.
Answer:
True
Explanation:
The reality is, wet signatures can easily be forged and tampered with, while electronic signatures have many layers of security and authentication built into them, along with court-admissible proof of transaction.
The end-to-end processes that need to appear in the process landscape model are:
- Design
- Plan
- Services
- Stores, etc.
<h3>What are the end-to-end processes?</h3>
End-to-end is known to be a term that connote a process that takes a system or service from the start to finish.
Note that it often delivers a full functional solution, and it is one that is without needing to get anything from a third party.
The process landscape is known to be made up of domain map that tends to captures core processes of industrial firms such as forecast to plan and others.
Hence, The end-to-end processes that need to appear in the process landscape model are:
- Design
- Plan
- Services
- Stores, etc.
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<span>getchar() only reads a single character input from any input stream.
getche() </span><span>reads a single character from the keyboard and displays immediately on output screen without waiting for enter key
scanf() reads the whole input line according to the data type you specified.</span>
Answer:
The answer is below
Explanation:
Given that:
Frame transmission time (X) = 40 ms
Requests = 50 requests/sec, Therefore the arrival rate for frame (G) = 50 request * 40 ms = 2 request
a) Probability that there is success on the first attempt =
but k = 0, therefore Probability that there is success on the first attempt = 
b) probability of exactly k collisions and then a success = P(collisions in k attempts) × P(success in k+1 attempt)
P(collisions in k attempts) = [1-Probability that there is success on the first attempt]^k = ![[1-e^{-G}]^k=[1-0.135]^k=0.865^k](https://tex.z-dn.net/?f=%5B1-e%5E%7B-G%7D%5D%5Ek%3D%5B1-0.135%5D%5Ek%3D0.865%5Ek)
P(success in k+1 attempt) = 
Probability of exactly k collisions and then a success = 
c) Expected number of transmission attempts needed = probability of success in k transmission = 