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ludmilkaskok [199]
3 years ago
14

What are the core scripting and coding technolies used to build ai platforms?

Computers and Technology
1 answer:
boyakko [2]3 years ago
4 0
<span>Artificial Intelligence is a huge field. </span>
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How important are operating system in our devices?​
TiliK225 [7]

Answer:

Explanation:

An operating system is the most important software that runs on a computer. ... It also allows you to communicate with the computer without knowing how to speak the computer's language. Without an operating system, a computer is useless.

6 0
2 years ago
Read 2 more answers
Hydraulic pressure is the same throughout the inside of a set of brake lines. What determines the amount of resulting mechanical
cestrela7 [59]

Answer: 1000 square ponds of force hope you know the answer

Explanation: i guessed

7 0
2 years ago
Write a complete Java program called Rooter that gets a positive integer called "start" from the user at the command line and th
Nataly_w [17]

Answer:

The program in Java is as follows:

import java.util.*;

import java.lang.Math;

public class Rooter{

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

 int start;

 System.out.print("Start: ");

 start = input.nextInt();

 while(start<=0){

     System.out.print("Number must be positive\nStart: ");

     start = input.nextInt();  }

 while(start>=0){

     System.out.println(Math.sqrt(start));

     start--;  }

}

}

Explanation:

This declares start as integer

 int start;

This prompts the user for input

 System.out.print("Start: ");

This gets input for start

 start = input.nextInt();

The following is repeated until the user input is valid i.e. positive

<em>  while(start<=0){</em>

<em>      System.out.print("Number must be positive\nStart: ");</em>

<em>      start = input.nextInt();  }</em>

The following while loop prints the square root of each number till 0

<em>  while(start>=0){</em>

<em>      System.out.println(Math.sqrt(start));</em>

<em>      start--;  }</em>

4 0
2 years ago
The 'client area' of a window is the area used to display the contents of the window (thus a title bar or border would lie outsi
Stolb23 [73]

Answer:

The Java code is given below

Explanation:

<u>Window.java: </u>

public class Window {

private int width, height;

public Window(int width, int height) {

this.width = width;

this.height = height;

}

public int getHeight() {

return height;

}

public void setHeight(int height) {

this.height = height;

}

public int getWidth() {

return width;

}

public void setWidth(int width) {

this.width = width;

}

@Override

public String toString() {

return "Window [width=" + width + ", height=" + height + "]";

}

}

<u>TitledWindow.java: </u>

public class TitledWindow extends Window {

private int barHeight;

public TitledWindow(int width, int height, int barHeight) {

super(width, height);

this.barHeight = barHeight;

}

public int getClientAreaHeight() {

return barHeight + super.getHeight();

}

@Override

public String toString() {

return "TitledWindow [width=" + super.getWidth() + ", height=" + super.getHeight() + ", barHeight=" + barHeight + "]";

}

}

<u>TestWindows.java: </u>

public class TestWindows {

public static void main(String args[]) {

Window w = new Window(450, 200);

System.out.println("Window: " + w);

TitledWindow titledWindow = new TitledWindow(450, 200, 30);

System.out.println("titaledWindow: " + titledWindow);

System.out.println("titledWindow.height: " + titledWindow.getClientAreaHeight());

}

}

6 0
3 years ago
c programming Write code that prints: Ready! countNum ... 2 1 Go! Your code should contain a for loop. Print a newline after eac
olga_2 [115]

Answer:see explanation

Explanation:

Hello, from your question I see that you need a program which based on countNum's value prints ready then all the numbers to 1 and finally go!, I'd appreciate if you provided information about the numbers after the example you gave as I do not know if they are to be printed too.

The solution I provide includes the countdown to 1 printing newline after each number and text. Try it out!

#include <stdio.h>

int main(void)

{

   int countNum;

   int i;

   countNum = 22;

   for ( i = countNum; i > 0; i--) {

       if (i == countNum){

           printf("Ready!\n");

       }

       printf("%d\n",i);

   }

   printf("Go!\n");

   return 0;

}

6 0
3 years ago
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