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il63 [147K]
3 years ago
15

Three tenths plus five eigths

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
4 0
The answer would come out to be 37/40
lianna [129]3 years ago
3 0
To add/subtract fractions you need to have a common denominator...

3/10+5/8  so we want to make the common denominator the least common multiple...

(3/10)(4/4)+(5/8)(5/5)

12/40+25/40

(12+25)/40

37/40
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Add (-x^2-2x+6)+(-9x^2-7x+6)
77julia77 [94]

(-x²-2x+6)+(-9x²-7x+6) = -x²-2x+6-9x²-7x+6 = -10x² - 9x + 12

5 0
3 years ago
Work out the surface area of a cylinder when the height = 18cm and the volume = 1715cm cubed
lara [203]

Answer:

813.4 cm² (nearest tenth)

Step-by-step explanation:

<u>Volume of a cylinder</u>

\sf V=\pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

Given:

  • h = 18cm
  • V = 1715 cm³

Use the Volume of a Cylinder formula and the given values to find the <u>radius of the cylinder</u>:

\implies \sf 1715=\pi r^2 (18)

\implies \sf r^2=\dfrac{1715}{18 \pi}

\implies \sf r=\sqrt{\dfrac{1715}{18 \pi}

<u>Surface Area of a Cylinder</u>

\sf SA=2 \pi r^2 + 2 \pi r h \quad\textsf{(where r is the radius and h is the height)}

Substitute the given value of h and the found value of r into the formula and solve for SA:

\implies \sf SA=2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)^2 + 2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)(18)

\implies \sf SA=2 \pi \left(\dfrac{1715}{18 \pi} \right) + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)

\implies \sf SA=\dfrac{1715}{9} + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)

\implies \sf SA=813.3908956...

Therefore, the surface area of the cylinder is 813.4 cm² (nearest tenth)

8 0
2 years ago
Read 2 more answers
Solve system by elimination<br> y=x^2<br> y=x+2<br> SHOW YOUR WORK
Dimas [21]
We have that
y=x²----> equation 1<span>
y=x+2-----> equation 2

multiply equation 1 by -1
-y=-x</span>²

add equation 1 and equation 2
-y=-x²
 y=x+2
------------
0=-x²+x+2-------------> -x²+x+2=0-----> x²-x-2=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x²-x)=2
<span>Complete the square. Remember to balance the equation by adding the same constants to each side
</span>(x²-x+0.5²)=2+0.5²

Rewrite as perfect squares

(x-0.5)²=2+0.5²
(x-0.5)²=2.25-----> (x-0.5)=(+/-)√2.25-----> (x-0.5)=(+/-)1.5
x1=1.5+0.5-----> x1=2
x2=-1.5+0.5---- > x2=-1

for x=2
y=x²----> y=2²----> y=4
the point is (2,4)

for x=-1
y=x²----> y=(-1)²---> y=1
the point is (-1,1)

the answer is
the solution of the system are the points
(2,4) and (-1,1)


3 0
3 years ago
CAN SOMEONE PLS HELP A GIRL OUT T-T
azamat

\frac{(13 - 6) {}^{11} }{((2 + 5)^{4} ){}^{2}  }

\frac{(7) {}^{11} }{((7) {}^{4})^{2} }

\frac{7 {}^{11} }{7 {}^{8} }

7 {}^{(11 - 8)}

7 {}^{3}

343

8 0
3 years ago
Which equation is an identity?
miskamm [114]

Answer:

D

Step-by-step explanation:

To be an identity we require both sides of the equation to equate

A

8x + 9 ≠ 8x - 3 ← not an identity

B

7x - 2 = 8x + 4 - x = 7x + 4 ≠ 7x - 2 ← not an identity

C

11 - (2x + 3) = 11 - 2x - 3 = - 2x + 8 ≠ - 2x - 8 ← not an identity

D

5x + 8 - x = 6x - 2(x - 4), that is

4x + 8 = 6x - 2x + 8 = 4x + 8 ← both sides equate thus an identity

5 0
3 years ago
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