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Talja [164]
2 years ago
12

I had this question that said What is 3 common multiples of 2 and 6 can someone answer please I can’t find anything online eithe

r
Mathematics
1 answer:
JulijaS [17]2 years ago
5 0

Answer:6,12,18

Step-by-step explanation:

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Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers
slamgirl [31]

Answer:

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

Step-by-step explanation:

Let be \vec u = (2,-3), its unit vector is determined by following expression:

\hat {u} = \frac{\vec u}{\|\vec u \|}

Where \|\vec u \| is the norm of \vec u, which is found by Pythagorean Theorem:

\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}

\|\vec u\| = \sqrt{13}

Then, the unit vector is:

\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)

\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right)

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

6 0
3 years ago
What is the solution of the system of equations?<br><br> {3x−1/2y=−7/2 x+2y=1
k0ka [10]
3x -1/2y = -7/2
x = -2y + 1

3 (-2y + 1) -1/2y = -7/2
-6y +3 -1/2y = -7/2
-13/2y = -13/2
y = 1

x = -2(1) + 1
x = -1

Answer = (-1, 1)
4 0
3 years ago
A number is chosen at random from 1-50. find the probability of selecting composite numbers
Ganezh [65]
.68 or a 68% chance
8 0
3 years ago
Read 2 more answers
28a-4a^2<br> Helpp it’s simplifying
olga nikolaevna [1]

Answer:

{ \tt{ = 28a -  {4a}^{2} }} \\  = 4a(7 - a)

4 0
3 years ago
For what value of the constant c is the function fcontinuous on (−[infinity], [infinity])?
Arlecino [84]

Answer:

For c=\frac{1}{7} the function f(x) is continuous on (-\infty,\infty).

Step-by-step explanation:

We have the following function

f(x) = \left\{        \begin{array}{ll}            cx^2+5x & \quad x

For the function f(x) to be continuous on (-\infty,\infty) it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that

\lim_{x \to 6^{-} } f(x)=\lim_{x \to 6^{+} } f(x)=f(x),

which holds if and only if

c\left(6\right)^2+5\left(6\right)=\left(6\right)^2-c\left(6\right)\\36c+30=36-6c\\42c=6

namely if c=\frac{1}{7}.

6 0
2 years ago
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