The ball will bounce 72 cm high if dropped from a height of 120 cm
<u>Solution:</u>
Given, The height that a ball bounces varies directly with the height from which it is dropped.
A certain ball bounces 30 cm when dropped from a height of 50 cm.
We have to find how high will the ball bounce if dropped from a height of 120 cm?
Now, according to given information,
When dropped from 50 cm ⇒ bounces 30 cm
Then, when dropped from 120 cm ⇒ bounces "n" cm
Now by Chris cross method, we get,
Hence, the ball bounces 72 cm high.
Answer:
1) suplimentary = a total of 180°
x + 9x = 180
10x = 180
2) complimentary = a total of 90
x + 2x = 90
Answer:
A. (x,y) - (2x,2y)
Step-by-step explanation:
Answer: X=-6.4 or 6 4/10
Step-by-step explanation:
X/12+1/3=-1/5
-1/3. -1/3
X/12=-8/15
*12. *12
X=-6.4 or -6 4/10
We know that
slope m=(y2-y1)/(x2-x1)
then
case a) x=18
m=(y2-y1)/(18-18)--------------> is undefined, because <span>the denominator is zero
case b) </span><span>2y-6x=0
2y=6x------------> y=3x
the slope m=3-----------> m is defined
case c) y=9
</span>m=(9-9)/(x2-x1)--------> m=0-----------> m is defined
case d) y=x
m=1---------------> m is defined
the answer is
x=18 has an undefined slope