3 years ago

Hello please help i’ll give brainliest

Mathematics

1 answer:

MAXImum [283]3 years ago

8 0

Answer:

Just a little puppy

hope this helped

Step-by-step explanation:

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Kiran shops for books during a 20% off sale. Write an equation that relates the sale price, s, to the original price p.

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Answer:

s=p*.2

Step-by-step explanation:

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3 years ago

Using this formula, what is the acceleration of an object with F=7.92 newtons and m=3.6 kilograms? Express your answer to the ne

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2.2

Step-by-step explanation:

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3 years ago

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Korolek [52]

Answer:

the first one is 5/12 and the second one is 6/28. Hope this helps and have a nice day:)

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3 years ago

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Answer:

5/9 of a chance

Step-by-step explanation:

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4 years ago

Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.

leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

$12x-5y+14=0 \\ 12x-5y-14=0$

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1$

$\Rightarrow 12h-5k-1=\pm 13$

$\Rightarrow 12h-5k=\pm 14$

$\Rightarrow 12h-5k=14,\ 12h-5k=-14$

$\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0$

$\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0$

Two equations are formed because one will be upper from the the given line and other will be below it.

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3 years ago