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anygoal [31]
4 years ago
13

7 over 3 divided by 6​

Mathematics
2 answers:
lesya692 [45]4 years ago
8 0

Answer:

\frac{7}{18}

Step-by-step explanation:

We want to simplify;

\frac{7}{3}\div6

This can be rewritten as;

\frac{7}{3}\div \frac{6}{1}

We multiply by the reciprocal of the second fraction to obtain;

\frac{7}{3}\times \frac{1}{6}

We multiply to get;

=\frac{7\times1}{3\times6}

=\frac{7}{18}

boyakko [2]4 years ago
4 0

7

3

÷

6

7

3

÷

6

Rewrite the division as a fraction.

7

3

6

7

3

6

Multiply the numerator by the reciprocal of the denominator.

7

3

⋅

1

6

7

3

⋅

1

6

Simplify

7

3

⋅

1

6

7

3

⋅

1

6

.

Multiply

7

3

7

3

and

1

6

1

6

.

7

3

⋅

6

7

3

⋅

6

Multiply

3

3

by

6

6

.

7

18

7

18

The result can be shown in multiple forms.

Exact Form:

7

18

7

18

Decimal Form:

0.3

¯

8

0.38‾

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4 0
3 years ago
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Sergeeva-Olga [200]

Answer:whaaaat?

Step-by-step explanation:

5 0
3 years ago
Is 87656432 divisible by 4? Is there a shortcut?
Natasha2012 [34]
Hope this isn't too confusing

All of the numbers have different shortcuts.
1. Yes. Divisible by 4: if last two digits are divisible by 4 then the whole number is yes)
2. No. Divisible by 6: it must be even and when you add them up, (44) it must be divisible by 3 (no, 44 is not divisible by 3)
3. Divisible by 8: ( last 3 numbers are divisible by 8 (312) = 39 ( yes it is)
4 Yes. Divisible by 11: ( sum of digits at odd places and sum of digits at even spaces,is either 0 or divisible by 11) yes, 278949. (2+8+9) + (7+9+9)= 19 + 25 = 44 and 44 is divisible by 11)
5. No. Divisible by 12 (divisible by 3 and 4, sum of digits is divisible by 3 ; and last 2 digits divisible by 4: 87654395 : 52/3= 18 (yes) 95/4(no) this number not divisible by 12
6. No. Divisible by 15: divisible by 3 and 5 ..87654385 = 46/3 = 15..(No) divisible by 5 yes. The number is not divisible by 15

8 0
3 years ago
Is the dilation of -3/4 a contraction or an expansion?
lyudmila [28]
I don't under stand
5 0
3 years ago
Plz help me on this
Margarita [4]
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