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anygoal [31]
3 years ago
13

7 over 3 divided by 6​

Mathematics
2 answers:
lesya692 [45]3 years ago
8 0

Answer:

\frac{7}{18}

Step-by-step explanation:

We want to simplify;

\frac{7}{3}\div6

This can be rewritten as;

\frac{7}{3}\div \frac{6}{1}

We multiply by the reciprocal of the second fraction to obtain;

\frac{7}{3}\times \frac{1}{6}

We multiply to get;

=\frac{7\times1}{3\times6}

=\frac{7}{18}

boyakko [2]3 years ago
4 0

7

3

÷

6

7

3

÷

6

Rewrite the division as a fraction.

7

3

6

7

3

6

Multiply the numerator by the reciprocal of the denominator.

7

3

⋅

1

6

7

3

⋅

1

6

Simplify

7

3

⋅

1

6

7

3

⋅

1

6

.

Multiply

7

3

7

3

and

1

6

1

6

.

7

3

⋅

6

7

3

⋅

6

Multiply

3

3

by

6

6

.

7

18

7

18

The result can be shown in multiple forms.

Exact Form:

7

18

7

18

Decimal Form:

0.3

¯

8

0.38‾

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What is the top half of a fraction called
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36, ___, ___, 32/3 is a geometric sequence, with some terms missing. First, please solve for "r", the common ratio between each
Ksju [112]

Answer: r = 2/3

Step-by-step explanation:

In a geometric sequence, the consecutive terms differ by a common ratio. The formula for determining the nth term of a geometric progression is expressed as

Tn = ar^(n - 1)

Where

a represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

From the information given,

a = 36

The 4th term is 32/3

n = 4

Therefore,

T4 = 32/3 = 36 × r^(4 - 1)

32/3 = 36 × r^3

Dividing both sides if the equation by 36, it becomes

32/3 × 1/36 = r^3

8/27 = r^3

Taking cube root of both sides of the equation, it becomes

(8/27)^1/3 = r^3 × 1/3

r = 2/3

3 0
3 years ago
When rolling two six-sided number cubes, what is the probability of getting a sum of at least 5? 5/18 1/3 13/18 5/6
VashaNatasha [74]

The sample space for two six sided cubes =

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)


Now the favourable events are those where the sum is greater than or equal to 5.

It means

(1,4) (1,5) (1,6)

(2,3) (2,4) (2,5) (2,6)

(3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)


It means

favourable events = 30

and total possible events = 36


So probability = 30/36   = 5/6

Hence 4th option is the correct one.

3 0
3 years ago
The common difference ,d in an arithmetic sequence whose fourth term is 16 and whose seventh therm is 31
Natali [406]

Answer: d=5

Step-by-step explanation:

Arithmetic progression

An=a1+d(n-1)

An= nth term

A1= first term

D= common difference

N= nth position

We are given the 4th and 7th terms

For 4th term,n=4

A4=a1+d(4-1)

A4= 16

16= a1+d(4-1)

16= a1+3d........equation 1

For the 7th term,n=7

A7=a1+d(7-1)

A7= 31

31=a1+6d......equation 2

Bring them together

16=a1+3d

31=a1+6d

Subtract equation 1 from 2

So we have

15=3d

D=15/3

D=5

Therefore, the common difference is 5

3 0
3 years ago
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