All categories

3 years ago

A train travels 58 kilometers in 4 hours, and then 80 kilometers in 4 hours. What is its average speed?

1 answer:

7 0

Average speed =

(total distance covered) / (time to cover the distance).

Total distance covered = (58km + 80km) = 138 km

Time to cover the distance = (4hr + 4hr) = 8 hours

Average speed = 138km / 8hr = 17.25 km/hour .

(That's less than 11 mph. You could bike there faster!)

You might be interested in

If I had 10 cookies and promised my friend to give them 2 how many cookies will i have

Ksivusya [100]

Answer:

8 cookies

Step-by-step explanation:

edit one:the answer was 10 cookies, so please go give the person who said 10 cookies first some thanks/brainliest.

edit two:brainly.com/app/profile/31525083 is the user who got it first. Check comment if you are gonna say they didn't.

6 0

3 years ago

Read 2 more answers

A puppy weighs534pounds.

Over [174]

The puppy weighs 92 oz

5 0

2 years ago

The points (12, 23) and (14, 45) lie on a line. What is<br> the slope of the line?

ozzi

Answer:

slope= 11

Step-by-step explanation:

(12,23) = (x1,y1)

(14,45) = (x2,y2)

Now,

slope(m)= (y2-y1)/(x2-x1)

=(45-23)/(14-12)

=22/2

=11

5 0

3 years ago

PLEASE ANSER URGENT !!!!!

Lynna [10]

The answer is 6/13 since there are 12 distinct letters in the phrase and 12/26 is written as 6/13

3 0

3 years ago

Please help

Alekssandra [29.7K]

Answer:

25 in x 15 in

Step-by-step explanation:

Given:

Length = 3/5 the width
Area = 375 in²

Let width = $x$

Therefore, length = 3/5 $x$

First create an equation for the area of the picture based on the given information for its width and length:

$\begin{aligned} \implies \textsf{Area of original picture} & = \sf width \times length\\& = x\left(\dfrac{3}{5}x\right)\\& = \dfrac{3}{5}x^2\end{aligned}$

We are told the area of the enlarged picture is 375 in². Therefore, substitute this into the equation and solve for $x$ to find the width of the enlarged picture:

$\begin{aligned}\textsf{Area} & = 375\\ \implies \dfrac{3}{5}x^2 & = 375\\ x^2 & =375 \cdot \dfrac{5}{3}\\ x^2 & =625\\ x & = \sqrt{625}\\ x& = 25\end{aligned}$

Therefore, the width of the enlarged picture is 25 in.

Substitute the found value of $x$ into the expression for length to find the length of the enlarged picture:

$\begin{aligned}\sf Length & = \dfrac{3}{5}x\\\\\implies \sf Length & = \dfrac{3}{5}(25)\\\\& = 15\: \sf in\end{aligned}$

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>. The width is 25 in and the length is 15 in, as the length is 3/5 of the width.

5 0

2 years ago