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Makovka662 [10]
3 years ago
9

the length of a rectangle is twice its width. the perimeter of the rectangle is no more than 174cm. what is the greatest possibl

e value for the width?
Mathematics
1 answer:
Feliz [49]3 years ago
4 0
Hey there
I 've already answered this question twice
by mistake.Kindly check.

You might be interested in
Find length of each side
IgorLugansk [536]

Option b: 10 in, 18.5 in, 31.5 in.

Explanation:

The three sides of a triangle are 2y+1, 3y+5 and 7y

The perimeter of the triangle is 60 in.

Since, Perimeter = all sides of the triangle

Let us add all the three sides to determine the length of each side.

Perimeter=2y+1+3y+5+7y

Substituting the value of Perimeter and simplifying, we get,

60=12y+6\\54=12y\\4.5=y

Substituting y=4.5 in the three sides of the triangle 2y+1, 3y+5 and 7y, we get,

2y+1=2(4.5)+1=10 in

3y+5=3(4.5)+5=18.5 in

7y=7(4.5)=31.5 in

Thus, the lengths of each side are 10 in, 18.5 in, 31.5 in.

8 0
3 years ago
A) 1.0 mile <br>b) 5.0 mile <br>c) 5.8 mile <br>d) 0.8 mile ​
nordsb [41]

Answer:

d) 0.8 mile

Step-by-step explanation:

Coordinate of object B = (6, 6)

Coordinate of object C = (1, 4)

Coordinate of the archaeologist = (6, 1)

✍️Distance between Object B (6, 6) and the archaeologist (6, 1):

Distance = |6 - 1| = 5 units = 5 miles

✍️Distance between Object C (1, 4) and the archaeologist (6, 1):

Using the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, we would have:

d = \sqrt{(6 - 1)^2 + (1 - 4)^2}

d = \sqrt{(5)^2 + (-3)^2}

d = \sqrt{25 + 9}

d = \sqrt{34} = 5.8 units = 5.8 miles (nearest tenth)

Comparing how far each object is from the archaeologist, object C is 0.8 mile (5.8 - 5 = 0.8) farther than object B.

3 0
3 years ago
Please help as soon as you can
Tcecarenko [31]
It’s an integer, rational number, and a whole number
7 0
3 years ago
Four times one number minus three times another number is 12. Two times the first number added to three times to the second numb
SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

x = first number, y = second number

4x - 3y = 12

2x + 3y = 6

------------------add

6x = 18

x = 18/6

x = 3

4x - 3y = 12

4(3) - 3y = 12

12 - 3y = 12

-3y = 12 - 12

-3y = 0

y = 0

solution : (3,0)

4 0
3 years ago
Given that A = (4,3,-4), B = (2,8,-5) and C = (-5,5,-8), find the vector from A to the midpoint of BC.
viktelen [127]
Mid-point of BC, M=(2+(-5),8+5,-5+(-8))/2=(-1.5, 6.5, -6.5)
Vector from A to M = M-A=<(-1.5,6.5,-6.5)-(4,3,-4)>=<-11/2,7/2,-5/2>


6 0
3 years ago
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