we are given

now, we can compare it with

we can find b
we get

now, we are given
How would the graph change if the b value in the equation is decreased but remains greater than 1
Let's take
b=1.8

b=1.6

b=1.4

b=1.2

now, we can draw graph
now, we will verify each options
option-A:
we know that all y-value will begin at y=0
because horizontal asymptote is y=0
so, this is FALSE
option-B:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
option-C:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is TRUE
option-D:
we know that curves are increasing
so, the value of y will keep increasing as x increases
so, this is TRUE
option-E:
we can see that
curve is moving upward when b decreases for negative value of x
but it is increasing slowly for negative values of x
so, this is FALSE
To solve the problem above, we will be using the equation in solving the surface area of a cylinder which goes. A = 2pi r^2 + 2pi r h, A is for the surface area, pi is 3.1416; h is the height and r is the radius. Basing on this formula the radius will be 0.3982 ft both top and bottom.
Answer:
Money Ivan gets extra = 120 - 30 (or 3x) = 90
Step-by-step explanation:
Ivan = 4x
Tanya = 1x
Total = 150
4x + x = 150
5x = 150 ; x = 150 / 5 = 30
Ivan = 4x = 120
Tanya = 1x = 30
Money Ivan gets extra = 120 - 30 (or 3x) = 90
It would be 4 √7 that’s what i got