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3 years ago

Write 26 to 96 as a ratio in simplest form

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

8 0

$26:96=\frac{26}{96}=\frac{13 \times 2}{48 \times 2}=\frac{13}{48}=\boxed{13:48}$

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The _______ form of a quadratic equation is written y = a(x - h)2 + k.

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its wrong

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3 years ago

PLZ HELP ASAP TANGENTS OF CIRCLES PROBLEMS

quester [9]

A circumscribed angle is that which is formed by the intersection of the two tangent lines in a circle. With this, we can conclude that segments AC and AB are tangent to circle O. The tangent lines forms a right angle with the radius of the circle drawn from the center of the circle to the tangent point.

By the explanation above, we can say that angles C and B are equal to 90° and that triangle ACO and triangle ABO are congruent. Which means that segment AC is equal to segment AB. Thus, the length of AB is also 4.

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3 years ago

the second of two number is 6 more than 3 times the first. The sum of the two number is 30. Find the two numbers

pantera1 [17]

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4 years ago

Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =

vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

The options of the question are

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

$a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2$

$a_1=8$

Find the value of $a_2$

For n=2

$a_2=2.9(a_1)-0.2(a_1)^2$

$a_2=2.9(8)-0.2(8)^2=10.4$

Find the value of $a_3$

For n=3

$a_3=2.9(a_2)-0.2(a_2)^2$

$a_3=2.9(10.4)-0.2(10.4)^2=8.528$

For n=4

$a_4=2.9(a_3)-0.2(a_3)^2$

$a_4=2.9(8.528)-0.2(8.528)^2=10.1858$

For n=5

$a_5=2.9(a_4)-0.2(a_4)^2$

$a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887$

therefore

The population alternates between increasing and decreasing

7 0

3 years ago

Read 2 more answers

Idently the graph of f(x) = 3(x - 1) - 4. Then identity the vertex and ads of symmetry find the minimum value of and describe wh

Vesna [10]

Answer:

See below

Step-by-step explanation:

I assume you mean $f(x) = 3(x-1)^2-4$

The equation is already in vertex form $f(x)=a(x-h)^2+k$ where $a$ affects how "fat" or "skinny" the parabola is and $(h,k)$ is the vertex. Therefore, the vertex is $(h,k)\rightarrow(1,-4)$ .

The axis of symmetry is a line where the parabola is cut into two congruent halves. This is defined as $x=h$ for a parabola with a vertical axis. Hence, the axis of symmetry is $x=1$ .

The minimum value is the smallest value in the range of the function. In the case of a parabola, the y-coordinate of the vertex is the minimum value. Therefore, the minimum value is $y=-4$ .

The interval where the function is decreasing is $(-\infty,1)$

The interval where the function is increasing is $(1,\infty)$

8 0

3 years ago