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2 years ago

Given a = 7.6, A = 50 degrees, and b = 4.3, use the Law of Sines to solve for B. Round

Mathematics

1 answer:

meriva2 years ago

3 0

Answer:

we need the figure, where is it

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Help my little brother

Marrrta [24]

Answer:

1) 6

2) 9

3) 80

4) 10

5) 4

6) 4

Step-by-step explanation:

1) 36 / 6 = 6

2) 45 / 5 = 9

3) 10 * 8 = 80

4) 5 * 2 = 10

5) 16 / 4 = 4

6) 12 / 3 = 4

Hope this helped!

4 0

2 years ago

Find the distance between the two given points. Round to the nearest tenth.

labwork [276]

Answer:

9.9

Step-by-step explanation:

5 0

3 years ago

The parking garage charges $3 for the first hour of parking and $1.45 for each additional hour.

Alika [10]

I don't know what you are asking but my best guess is it will be
$4.46 in total

8 0

2 years ago

Read 2 more answers

Question

tatiyna

Answer:

Wes

Step-by-step explanation:

This represents a positive correlation, meaning that when x increases, so does y. Because of x, y increases meaning that Wes is correct

3 0

1 year ago

It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha

stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

0.54% of the calls receive a busy signal, hence p = 0.0054.

A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

$P(X \geq 5) = 1 - P(X < 5)$

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009$

$P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062$

$P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218$

$P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513$

$P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903$

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295$

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0

1 year ago