If she rides at 12 miles per hour, we know that 45 minutes is three quarters of an hour, therefore just workout:
3/4 x 12 = 9
So she would travel 9 miles in 45 minutes.
The bones at the time they were discovered when the radioactive element carbon-14 has a half-life of total 5750 years are 10062.5-year-old.
<h3>What is half-lives?</h3>
Half lives is the time interval which is need to decay the atomic nuclei of a radioactive sample.
There is a scientist who determined that the bones from a mastodon had lost 70.3% of their carbon-14. Thus, the fraction remaining is,
f=1-(70.3/100)=1-0.703
f=1-(70.3/100)=0.297
Now the fraction remaining can be given as,
f=(1/2)ⁿ
Here, n is the half life elapsed. Put the value of fraction remaining.
0.297=(1/2)ⁿ
n=1.75
The radioactive element carbon-14 has a half-life of total 5750 years. Thus,
Years=1.75*5750
Years=10062.5
Thus, the bones at the time they were discovered when the radioactive element carbon-14 has a half-life of total 5750 years are 10062.5-year-old.
Learn more about the half lives here;
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Answer: Your equation would be A(J)=.50j + 5
Step-by-step explanation:
Answer:
Step-by-step explanation:
An eigenvalue of n × n is a function of a scalar 
considering that there is a solution (i.e. nontrivial) to an eigenvector x of Ax =
Suppose the matrix ![A = \left[\begin{array}{cc}-1&-1\\2&1\\ \end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%26-1%5C%5C2%261%5C%5C%20%5Cend%7Barray%7D%5Cright%5D)
Thus, the equation of the determinant (A - 1) = 0
This implies that:
![\left[\begin{array}{cc}-1-\lambda &-1\\2&1- \lambda\\ \end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1-%5Clambda%20%26-1%5C%5C2%261-%20%5Clambda%5C%5C%20%5Cend%7Barray%7D%5Cright%5D%20%3D0)
Hence, the eigenvalues of the equation are 
Also, the eigenvalues can be said to be complex numbers.
It’s is greater it would only be equal if you multiplied it by 100
