What is the solution, if any, to the inequality |3x|2O?
1 answer:
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Answer: The mean of the frequency distribution is 51.7°.
The computed mean 51.7° is greater than the actual mean 50.7° .
Step-by-step explanation:
The given table :
Low Temperature (°F) Frequency Mid -value
Class interval f x fx
40-44 2 42.5 85
45-49 7 47.5 95
50-54 9 52.5 105
55-59 5 57.5 115
60-64 1 62.5 25
The computed mean 51.7° is greater than the actual mean 50.7° .
Answer:
The correct option is;
C. 3. ∠BDE ≅∠BAC, Corresponding Angles Postulate 4. ∠B ≅ ∠B Reflexive Property of Equality
Step-by-step explanation:
The two column proof can be written as follows;
Statement, Reason
1. , Given
2. is a transversal , Conclusion from statement 1.
We note that ∠BDE and ∠BAC are on the same side of the transversal relative to the parallel lines, and are therefore, corresponding angles.
Therefore, we have;
3. ∠BDE ≅∠BAC, Corresponding Angles Postulate
Also
4. ∠B ≅ ∠B, Reflexive Property of Equality
In the two triangles, ΔABC and ΔDBE, we have ∠BDE ≅∠BAC and ∠B ≅ ∠B,
From ∠BDE + ∠B + ∠BED = 180°
∠BAC + ∠B + ∠BCA = 180°
Therefore, ∠BED = ∠BCA Substitution property of equality
Which gives;
5, ΔABC ~ ΔDBE, Angle Angle Similarity Postulate
6. BD/BA = BE/BC, Converse of the Side-Side-Side Similarity Theorem