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Stells [14]
3 years ago
12

Can someone tell me if I’m wrong or right and help with the last two questions

Mathematics
1 answer:
algol [13]3 years ago
6 0

Answer:

you are right

Step-by-step explanation:

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Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3
Nikitich [7]

Answer:

option D

Step-by-step explanation:

f(x) = x^2 + 5x + 6

g(x)= \frac{1}{x+3}

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x  in f(x)

f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6

To simplify it we take LCD

LCD is (x+3)(x+3)

\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}

\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}

All the denominators are same so we combine the numerators

\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}

\frac{6x^2+41x+70}{x^2+6x+9}

Option D is correct

8 0
3 years ago
Read 2 more answers
Miranda needs to cut strips of paper that are 1/8 of an inch. If she has piece of paper that is 7 and 3/4 inches long. How many
Sloan [31]

Answer:

62

if you turn 1/8 and 7 3/4 to decimals they turn into 1/8=0.125 and 7 3/4=7.75 and 7.75/0.125=62

8 0
3 years ago
Solve the following function for y when x=5 round to the nearest tenth
Wittaler [7]

In the given question , we have a function given , which is

y= 13(0.5^x)

And we need to find the value of y when x=5.

So we substitute 5 for x and solve for y, that is

y=13(0.5^5) = 0.40625

And on rounding to the nearest tenths, we will get

y=0.4

So when x=5, y=0.4

7 0
3 years ago
Jeremy's father drives him to school in rush hour traffic in 20 minutes. One day there is no traffic, so his father can drive hi
umka21 [38]

Answer:

Step-by-step explanation:

18/60-12/60= 4 miles

just my guess

6 0
3 years ago
PLISS ANSWER :C DONT ANSWER IF YDK THAnKSSS<br> *also pls look at both images :)*
Iteru [2.4K]

Answer:

First image: (6, -1)

2nd image: y = 63

Explanation:

1)

2x + y = 11

1/2x - 5y = 8

y = -2x + 11

1/2x - 5(-2x + 11) = 8

1/2x + 10x - 55 = 8

10.5x - 55 = 8

10.5x = 63

x = 6

2x + y = 11

2(6) + y = 11

12 + y = 11

y = -1

(x , y) = (6, -1)

2)

1/4(8y - 4.8) = 2 (0.9y + 5.4) + 3/5

2y - 1.2 = 1.8y + 10.8 + 0.6

0.2y - 1.2 = 11.4

0.2y = 12.6

y = 63

7 0
3 years ago
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