24 students ===> 100% of the third test &
150% of the second test is 150% of 24 students:
So the 150% in the second test correspond to 150% x 24 = 36
Answer:3/4
Step-by-step explanation:
Answer: 0.0688
Step-by-step explanation:
Given : Current research indicates that the distribution of the life expectancies of a certain protozoan is normal with a mean of 43 days and a standard deviation of 10.1 days.
i.e.
and 
Let x represents the life expectancies of a certain protozoan.
Sample size : n= 25
The probability that a simple random sample of 25 protozoa will have a mean life expectancy of 46 or more days. :-

[using z-value table]
Hence, the required probability = 0.0688
Answer:
m = -1/2
Step-by-step explanation:
<u>Step 1: Solve for m</u>
6m + 3 - 3 = 0 - 3
6m / 6 = -3 / 6
m = -3/6
m = -1/2
Answer: m = -1/2