ANSWER:
65.7g of sugar
STEP BY STEP:
multiply the amount of sugar needed for one cake (7.3) by the number of cakes you want to make (9). And you get your answer of 65.7.
hope this helps
Answer: none
Step-by-step explanation:
(A)
(16÷32/10) ×2 + 0.2×(90)
Using bodmas principle ; solve bracket
(16×10/32)×2 + (2/10×90)
10+18 =28
(B)
{(16÷32/10) × (2+2/10)} ×90
Open brackets
{(16×10/32) × (22/10)} ×90
(5×11/5) ×90
11×90 = 990
(C)
16÷{(32/10×2) + (2/10×8)} +82
Open brackets, solve division first, dolled by addition
16÷(32/5 + 8/5) +82
16÷(40/5) +82
16÷8 +82
2+82= 84
(D)
[16÷(32/10 ×2) + 0.2× (90)]
16÷ (32/5) + 2/10 ×90
Solve division
16×5/32 + 18
5/2 + 18
L.c.m of denominator (2&1) =2
(5+36) / 2 = 41/2
=20.5
To solve this problem you must apply the proccedure shown below:
1. You have that Jim drove the car 2,718.3 miles for a total mileage of 87,416.
2. Then, to calculate the mileage before last month, you only need to substract the total mileage given in the exercise above and the mileage drove last month, as following:
Therefore, the answer is: 84,697.7 miles.
Answer:
x=-1
Step-by-step explanation:
4x-16=-20
Get x to one side by subtracting it.
-16=-20-4x
Add the 20 on both sides.
-16+20=-4x
Simplify
4=-4x
4/-4=-4x/-4
-1=x
x=-1
Answer:
<u>First question answer:</u> The limit is 69
<u>Second question answer:</u> The limit is 5
Step-by-step explanation:
For the first limit, plug in 
in the expression 
, that's the answer for linear equations and limits.
So we have:
The answer is 69
For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value 
into the simplified expression to get the correct answer. Shown below:
<em>Now putting 1 in 
gives us the limit:</em>
So the answer is 5
