Question

A rectangle has a length that is 5 meters greater than the width. If w represents the width, write an expression, in terms of w, for the steam of the rectangle.

Answer 1

Answer:

Area of rectangle is $w^2+5w$

Perimeter of Rectangle is $4w+20$.

Step-by-step explanation:

Given:

Let the width of the rectangle be 'w'.

Also Given:

A rectangle has a length that is 5 meters greater than the width.

Length of rectangle = $w+5\ meters$

We need to write expression for Area of rectangle and Perimeter of rectangle.

Solution:

Now we know that;

Perimeter of rectangle is equal to twice the sum of the length and width.

framing in equation form we get;

Perimeter of rectangle = $2(w+5+w)=2(2w+5) =4w+20$

Also We know that;

Area of rectangle is length times width.

framing in equation form we get;

Area of rectangle= $w(w+5) = w^2+5w$

Hence Area of rectangle is $w^2+5w$ and Perimeter of Rectangle is $4w+20$.