Question

Kepler’s law states that if one object is in orbit around another, the square of the time it takes that object to complete a revolution varies directly with the cube of the average radius of the orbit. How is the time affected if the average radius is doubled?

Answer 1

Kepler's 3rd Law is t^2 = r^3
Let's say "r" is 2, then
t^2 = 8
t = 2.8284271247
Basically, t = r^1.5

If you want to know more about Kepler's 3rd Law click here:
http://www.1728.org/kepler3a.htm