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Art [367]
3 years ago
8

Kepler’s law states that if one object is in orbit around another, the square of the time it takes that object to complete a rev

olution varies directly with the cube of the average radius of the orbit. How is the time affected if the average radius is doubled?
Mathematics
1 answer:
Nitella [24]3 years ago
6 0
Kepler's 3rd Law is t^2 = r^3
Let's say "r" is 2, then
t^2 = 8
t = <span> <span> <span> 2.8284271247 </span> </span> </span>
Basically, t = r^1.5

If you want to know more about Kepler's 3rd Law click here:
http://www.1728.org/kepler3a.htm



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3 years ago
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Westkost [7]

Answer:

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In a triangle, the sum of any 2 sides must be larger than the third side.

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  (Inequality #1)   12 + 4 > x

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7 0
2 years ago
Can someone please help me answer this question please
Alinara [238K]

Answer:

1.791875241 ^{13}

This is answer

like

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2 years ago
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tangare [24]
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3 years ago
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