Kepler’s law states that if one object is in orbit around another, the square of the time it takes that object to complete a rev
olution varies directly with the cube of the average radius of the orbit. How is the time affected if the average radius is doubled?
1 answer:
Kepler's 3rd Law is t^2 = r^3
Let's say "r" is 2, then
t^2 = 8
t =
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2.8284271247
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Basically, t = r^1.5
If you want to know more about Kepler's 3rd Law click here:
http://www.1728.org/kepler3a.htm
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Step-by-step explanation:
( y = 4x/5 + 2)
m1.m2 = -1
4/5.m2 = -1
m2 = -5/4
formula = y - y1 = m2 ( x - x1)
y - 3 = -5/4 ( x - 6)
y -3 = -5x /4 + 30/4
y = -5x /4 + 21/2
Step-by-step explanation:
I need more information
Answer:
140 percent is the answer
90%
Because if you reduce the fraction 180/200 you get 90/100 or 90%