A recent survey showed that 47% of recent college graduate named flexible hours as their most desired employment benefit. in a g
1 answer:
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Answer:
[0.9 months, 32.69 months]
Step-by-step explanation:
The mean is
The standard deviation is
Now, we have to find two values a and b such that the area under the Normal curve with mean 16.8 and standard deviation 8.1092 between a and b equals <em>95% = 0.95 </em>
Using a spreadsheet we find these values are
a = 0.906
b = 32.694
<h3>(See picture) </h3>and our 95% confidence interval for the mean number of months elapsed since the last visit to a dentist for the population of students participating in the program rounded to two decimal places is
[0.9 months, 32.69 months]
