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3 years ago

PLEASE HELP ME I DONT UNDERSTAND MY HOMEWORK AND ITS TUE TODAY

Mathematics

2 answers:

Vera_Pavlovna [14]3 years ago

4 0

Answer:

n- 15 = 4 is the answer.

hope this is helpful ^_^

Scrat [10]3 years ago

3 0

Answer:

All of the above

Step-by-step explanation:

The question is asking you which equation you can use for you to find the value of the undefined variable, n.

In this case, all of the equations above are eligible to find the value of the variable n since regardless of the variable position, you will yet be able to find its value.

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What must be added to a^2+3/5a

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This question doesn’t really make sense- is it multiple choice, if so what are the options? A can be anything as long as it’s the same?

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2 years ago

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

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3 years ago

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Bogdan [553]

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3 years ago

Analyze the problem and complete the statements.

NARA [144]

Answer:

I know this problem is an

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2 years ago

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den301095 [7]

Answer:

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Step-by-step explanation:

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( 1+7)/2 = 8/2 = 4

The y coordinate of the midpoint is the sum of the y coordinates divided by 2

( 2+2)/2 = 4/2 = 2

The midpoint is (4,2)

3 0

3 years ago

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