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aleksandr82 [10.1K]
4 years ago
13

Answer this someone plz if you know how to do it

Mathematics
1 answer:
Nezavi [6.7K]4 years ago
5 0
The answer for this question would be B) 18/34 > 16/32 since it has infinitely many solutions, the statement can be classified as true.
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For 0 ≤ x < 2π, which of the following solves 2cos(StartFraction x Over 2 EndFraction + 1 = 0?
ICE Princess25 [194]

Answer:

a.{4pi/3}

Step-by-step explanation:

Edge

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I need to find the area of the crater
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Bradley completed 3/5 of his homework. What percent of his homework does he still need to complete?
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Find the circumference and area of a circle<br>with a diameter of 26 yards.​
bezimeni [28]

if the diameter is 26 yards, then its radius is half that, or 13 yards.

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=13 \end{cases}\implies C=2\pi (13)\implies C=26\pi \implies C\approx 81.68 \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=13 \end{cases}\implies A=\pi (13)^2\implies A=169\pi \implies A\approx 530.93

8 0
3 years ago
Jika garis 4x+ay = 8 dan ay=9x + 5 saling tegak lurus,maka nilai a
barxatty [35]

We are given equations as

4x+ay=8

Firstly, we will write in slope intercept form of line

y=mx+b

4x+ay=8

Subtract both sides by 4x

4x+ay-4x=-4x+8

ay=-4x+8

now, we can divide both sides by a

y=-\frac{4}{a} x+\frac{8}{a}

we can find slope

so, we get

m_1=-\frac{4}{a}

we are given second equation as

ay=9x+5

Firstly, we will write in slope intercept form of line

y=mx+b

divide both sides by a

y=\frac{9}{a} +\frac{5}{a}

we can find slope

m_2=\frac{9}{a}

we are given both lines are perpendicular

so, the multiplication of their slopes must  be -1

m_1\times m_2=-1

we can plug values

-\frac{4}{a}\times \frac{9}{a}=-1

now, we can solve for a

\frac{36}{a^2}=-1

Multiply both sides by a

\frac{36}{a^2}\times a^2=1\times a^2

36= a^2

now, we can solve for a

we get

a=-6,a=6...............Answer

4 0
4 years ago
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