Answer:
(a) y = -6(x -1)
(b) about 5.3%
Step-by-step explanation:
(a) The point used as the base for the linear approximation is (1, f(1)), where ...
f(1) = 3 -3·1² = 0
The slope of the line at that point is ...
f'(x) = 0 -3(2x) = -6x
f'(1) = -6·1 = -6
So, in point-slope form, the equation of the approximating line is ...
y = -6(x -1) +0
y = -6(x -1)
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(b) The approximate value of f(0.9) is then ...
y = -6(0.9 -1) = 0.6 . . . . approximate value of f(0.9)
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(c) The error in the approximation at x=0.9 is ...
error% = (0.6 -f(0.9))/f(0.9) × 100%
where f(0.9) = 3(1 -0.9²) = 3·0.19 = 0.57
error% = (0.6 -0.57)/0.57 × 100% = 0.03/0.57 × 100%
error% ≈ 5.263% ≈ 5.3%