Anyone know how to solve a functions equation such as x^2-x-x <0

Kryger [21]

Basically you find the data points and fill in the values. For Point J it is (2,4). They want you to do this: (2-4,4-6)...it then becomes (-2,-2).
So
J: (-2,-2)
K: (-1, -4)
I: (-2, -5)
Those are your new points. I hope this helps love! :)

8 0

3 years ago

Consider the equations 15x + 9y = 45 and 9x + 8y = 12. Solve the system of equations using elimination. Give your solution to th

True [87]

Answer:

(-5.77, 6.46)

Step-by-step explanation:

15x + 9y = 45 ----------- i

9x + 8y = 12----------------ii

Multiply equation i by 9 the coefficient of x in equ ii

And equation ii by 15 the coefficient of x in equ I

9 x 15x + 9y = 45 ----------- i

15 x 9x + 8y = 12----------------ii

135x+81y = 405

135x+120y= 180

Subtract equation ii from I

135x-135x+81y-(+120y)= 405-180

-39y=225

y = 225/-39 = -5.77

Insert the value of y in equ i

15x + 9y = 45

15x+9(-5.77) = 45

15x-51.92=45

15x = 45+51.92

15x= 96.92

x = 96.92/15= 6.46

(x,y) = (-5.77, 6.46)

x = 6.92/15

5 0

3 years ago

Find using Pythagorean theorem <br><br> Find the distance (2, 8) (3, -9)

Maru [420]

Answer:

√290

Step-by-step explanation:

( 2 - 3 )^2 + ( 8 + 9 )^2

= ( - 1 )^2 + 17^2

= 1 + 289

= 290

= √290

4 0

3 years ago

sharia has a full time job and earns 475$ each week but she starts looking for ways to increase her weekly earnings . sharia fin

Arlecino [84]

Answer:

12 hours

Step-by-step explanation:

Full time job:

Earning per week = $475

Part time job :

Earning per hour = $11

Number of working hours per week at per time job to increase weekly earning to atleast $600 ;

Let number of hours = h

Full time earning + earning per hour * (number of hours) ≥ 600

$475 + ($11 * h) ≥ 600

$475 + $11h ≥ 600

11h ≥ 600 - 475

11h ≥ 125

h ≥ 125 / 11

h ≥ 11.36

Hence, sharia will need to work for 12 hours per week

5 0

3 years ago

Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in

Law Incorporation [45]

Answer:

(a) 900

(b) [567.35 , 1689.72]

(c) [23.82 , 41.11]

Step-by-step explanation:

We are given that a sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms i.e.;

Sample mean, $xbar$ = 290 Sample standard deviation, s = 30 and Sample size, n = 20

(a) Point estimate of the population variance is equal to sample variance, which is the square of Sample standard deviation ;

$\sigma^{2}$ = $s^{2}$ = $30^{2}$

$\sigma^{2}$ = 900

(b) 90% confidence interval estimate of the population variance is given by the pivotal quantity of $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

P(10.12 < $\chi^{2}__1_9$ < 30.14) = 0.90 {At 10% significance level chi square has critical

values of 10.12 and 30.14 at 19 degree of freedom}

P(10.12 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 30.14) = 0.90

P( $\frac{10.12}{(n-1)s^{2} }$ < $\frac{1 }{\sigma^{2} }$ < $\frac{30.14}{(n-1)s^{2} }$ ) = 0.90

P( $\frac{(n-1)s^{2} }{30.14}$ < $\sigma^{2}$ < $\frac{(n-1)s^{2} }{10.12}$ ) = 0.90

90% confidence interval for $\sigma^{2}$ = $[\frac{19s^{2} }{30.14} , \frac{19s^{2} }{10.12}]$

= $[\frac{19*900 }{30.14} , \frac{19*900 }{10.12}]$

= [567.35 , 1689.72]

Therefore, 90% confidence interval estimate of the population variance is [567.35 , 1689.72] .

(c) 90% confidence interval estimate of the population standard deviation is given by ;

P( $\sqrt{\frac{(n-1)s^{2} }{30.14}}$ < $\sigma$ < $\sqrt{\frac{(n-1)s^{2} }{10.12}}$ ) = 0.90

90% confidence interval for $\sigma$ = $[\sqrt{\frac{19s^{2} }{30.14}} , \sqrt{\frac{19s^{2} }{10.12}} ]$

= [23.82 , 41.11]

Therefore, 90% confidence interval estimate of the population standard deviation is [23.82 , 41.11] .

7 0

3 years ago