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Mkey [24]
3 years ago
6

Anyone know how to solve a functions equation such as x^2-x-x <0

Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

Step-by-step explanation:

x^{2} -x-x 0

x^{2} -2x < 0

x^2-2x+1<1

(x-1)^2<1

-1<x-1<1

0<x<2

(x-1)^{2}(x-1)^{2}

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Answer:

A = 82.53 in²

Step-by-step explanation:

We use the circumference equation C = 2πr and the area equation A = πr².

Using the first equation and the given circumference (32 in), we find the radius of the circle, and then use this result to find the area of the circle.

         

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C = 2πr becomes r = ----------- and here r = ---------- = 5.10 in

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3 years ago
What is the value of x in the following equation?
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