3 years ago

Anyone know how to solve a functions equation such as x^2-x-x <0

Mathematics

1 answer:

MrRissso [65]3 years ago

6 0

Answer:

Step-by-step explanation:

$x^{2} -x-x$ 0

$x^{2} -2x$ < 0

x^2-2x+1<1

(x-1）^2<1

-1<x-1<1

0<x<2

$(x-1)^{2}$ $(x-1)^{2}$

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