Question

Anyone know how to solve a functions equation such as x^2-x-x <0

Answer 1

Answer:

Step-by-step explanation:

$x^{2} -x-x$ 0

$x^{2} -2x$ < 0

x^2-2x+1<1

(x-1）^2<1

-1<x-1<1

0<x<2

$(x-1)^{2}$$(x-1)^{2}$