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Nina [5.8K]
4 years ago
15

1. Simplity the following into lowest term 3x - 2 - 2x​

Mathematics
2 answers:
swat324 years ago
4 0

Answer:

x-2

best of luck!

Yakvenalex [24]4 years ago
3 0
The answer is X-2 ........
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What is the estimate of forgive 6in by 4in
NNADVOKAT [17]

Find area of the semi circle.

The diameter is, half of that would be the radius, which is 3.

\frac{\pi \cdot 3^2}{2} = 14.1

Find the area of the rectangle.

6 * 4 =24

Add the two areas together.

24 + 14.1 = 38.1

38.1in^2

6 0
3 years ago
Write an equation for the line that passes through the points (-4, 12) and<br> (3,-2)
Tju [1.3M]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Write an equation in point-slope form of the line through point J(–10, –9) with slope 3.
Alinara [238K]
Use point-slope formula---> y-y1=m(x-x1)
Let y1 equal -9, let x1 equal -10, and let m equal 3 
Plug in and solve
y-(-9)=3(x-(-10)
y+9=3(x+10)
y+9=3x+30
Subtract nine from both sides 
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7 0
4 years ago
A teacher wrote the following set of numbers on
Rama09 [41]

Answer:

Did you copy this down correctly?

Step-by-step explanation:

b = .125 which is rational

a is irrational because the square root of a prime number is irrational.

If c = 225....

then adding 2 rational numbers = rational sum

But adding (or multiplying) an irrational number to a rational number = irrational number.

6 0
3 years ago
Prove by induction that 7^2n+1 +1 is divisible by 8, for all nEN
fredd [130]

Answer:

See below.

Step-by-step explanation:

Base case:

Replace n with 1.

7^(2×1+1)+1

7^3+1

343+1

344

8 is a factor of 344 since 344=8(43).

Induction hypothesis:

Assume there is some integer n such that 7^(2k+1)+1=8n for positive integer k.

7^(2[k+1]+1)+1

7^(2k+3)+1

7^(2k+1+2)+1

7^(2k+1)7^2+1

49×7^(2k+1)+1

Induction step:

49×(8n-1)+1

49(8n)-49+1

49(8n)-48

8[49n-6]

This means 8 is a factor of 7^(2(k+1)+1)+1.

Thus, this proves for all positive integer n that 8 is a factor of 7^(2n+1)+1.

7 0
2 years ago
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