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Norma-Jean [14]
3 years ago
15

What is the solution to this system of linear equations?

Mathematics
2 answers:
zysi [14]3 years ago
6 0

The answer is (-1,3)

This is how I got it:

I plugged in the x and y.

x=-1

y=3

so instead of y-4x=7, it is 3-4(-1)=7

2 negatives make a positive.

now I solve (3+4=7)

next equation is 2y+4x=2 do the same thing as in the first equation. and get 6+-4 and equals 2

so in this case, the answer is (-1,3)



Bogdan [553]3 years ago
5 0

Good morning Sonny

y-4x=7

2y+4x=2

We need to solve -4x+y=7 for y

Now let's start by adding 4x to both sides

-4x+y+4x=7+4x

y=4x+7

Now substitute 4x+7 for y in 4x+2y=2 so we can find the value for x

4x+2y=2

4x+2(4x+7)=2

12x+14=2

Add -14 to both sides

12x=14-14=2-14

12x=-12

Now divide 12 to both sides so we can find x

12x/12=-12/12

x=-1

Now we need to find the value for y by substitute -1 for x in y=4x+7

y=4x+7

y=(4)(-1)+7

y=3

Work done ;)

Answer : x=-1 and y=3

               (-1,3)

                D


I hope that's help :0

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Help with num 4 please.​
kati45 [8]

Answer:

y=1/2(x-1)

Step-by-step explanation:

If x=t^2 and t>0, then t=sqrt(x).

If t=sqrt(x) or x^(1/2) and y =1-1/t, then y=1-x^(-1/2).

The x-intercept is when y=0.

So we need to solve 0=1-x^(-1/2) to find point P.

Add x^(-1/2) on both sides: x^(-1/2)=1.

Raise both sides to -2 power: x=1

So point P is (1,0).

Let's find tangent line at point (1,0).

We will need the slope so let's differentiate.

y'=0+1/2x^(-3/2)

y'=1/(2x^(3/2))

The slope at x=1 is y'=1/(2[1]^(3/2))=1/(2×1)=1/2.

Recall point-slope form is y-y1=m(x-x1).

So our line we are looking for is y-0=1/2(x-1)

Let's simplify left hand side y=1/2(x-1)

4 0
3 years ago
Write an equation in slope-intercept form for the line with slope -1/3 and y-intercept 7
Maurinko [17]
Since m is equal to slope your m is -1/3 then you put the x after. Your b is the y intercept so your equation is y=-1/3x+7
3 0
3 years ago
Question 22 of 49
kolezko [41]

Answer:

B

Step-by-step explanation:

It's less than 90 degrees

8 0
4 years ago
A circle with center at (12,−1) passes through (0,−1). Find the circumference and area of the circle in terms of p.
madreJ [45]

Answer:

C = 75.36

A = 452.16

Step-by-step explanation:

Find the radius r by finding the distance between (12,-1) and (0,-1) using the distance formula.

d = \sqrt{(12-0)^2 + (-1--1)^2} =\sqrt{(12)^2 + (0^2} =\sqrt{144+0} =\sqrt{144}=12

The radius is 12.

So the circumference of the circle is C = 2\pi r = 2\pi 12 = 24\pi = 75.36

So the area of the circle is A = \pi r^2\\A = \pi 12^2\\A = 144\pi\\A = 452.16

6 0
3 years ago
There were 27,000 people at a ball game in Los Angeles. The day's receipts were $204,000. How many people paid $13 for reserved
Studentka2010 [4]
21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
x + y = 27000
As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission(x*6) and those two add up and we get second equation
13y + 6x = 204000.
This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.
13y + 6*(27000 - y) = 204000
13y + 162000 - 6y = 204000
7y = 42000
y = 6000
x + 6000 = 27000
x = 27000 - 6000 = 21000
5 0
3 years ago
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