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LekaFEV [45]
3 years ago
10

How to solve...John made 70% of his baskets in basketball. He made 105 baskets. How many total baskets did he make?

Mathematics
1 answer:
quester [9]3 years ago
7 0
105 ÷ 70 = 1.5
1.5 * 30 = 45
105 + 45 = 150 total shots
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You have the option of buying 20 tickets at the fair for 15$ or 45 for 27$ which is te best deal
Lostsunrise [7]
45 tickets for 27$is definitely the best deal because if you go with the first option and buy it twice you will pay 25$for only 40 I can’t Explain properly but definitely 45 for 26$
3 0
2 years ago
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Simplify ( 16- sq root of 11) / -2
Usimov [2.4K]
(16 - Sqrt(11))/(-2)
= -8 +Sqrt(11)/2
4 0
3 years ago
4. (03.03 HC)
Kitty [74]

Answer:

A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones

Step-by-step explanation:

B. table : (8,8)(12,12)(14,16)(16,16)

               look at ur points...when x = 8, y = 8...so the table, when x = 8 has a

               value of 8

relation : f(x) = 8x - 5....when x = 8

             f(8) = 8(8) - 5

             f(8) = 64 - 5

             f(8) = 59....and the relation has a value of 59

Therefore, the relation has a greater value when x = 8 <==

C. f(x) = 8x - 5...when f(x) = 19

    19 = 8x - 5

     19 + 5 = 8x

    24 = 8x

    24/8 = x

    3 = x <==

7 0
3 years ago
Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based
Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for \mathrm{sinc}\,x about x=0:

\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}

Then the Taylor series for

f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt

is obtained by integrating the series above:

f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

We have f(0)=0, so C=0 and so

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

which converges by the ratio test if the following limit is less than 1:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}

Like in the linked problem, the limit is 0 so the series for f(x) converges everywhere.

7 0
3 years ago
A frog leaps 24 inches. The highest point in the jump is 6 inches. Assume the frog starts at (0,0). What quadratic function mode
Ivanshal [37]
The path is in the shape of a parabola, the horizontal length is 24, so the middle point is at x=12, the symmetry line is x=12, the highest point (the vertex) is at (12,6)
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next, find a by using either one of the two points, the starting point (0,0) or the end point (0,24). obviously (0,0) is easier to calculate:
0=a(0-12)² +6
a=-1/24
so the quadratic equation is y=-\frac{1}{24} (x-12)^2+6
5 0
3 years ago
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