3 years ago

True or False ? An isosceles with legs of length 6 and base angles of 72 will have an area equal to 18 sin 36 .

Mathematics

2 answers:

IgorLugansk [536]3 years ago

8 0

The answer is true!

Eva8 [605]3 years ago

5 0

Answer:I believe it's true but I'm not sure

Step-by-step explanation:

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Diagram shows a section of a bridge between the points A and K. The length of line segment is 640 meters. ∆ABC, ∆CDF, and ∆FJK a

Marta_Voda [28]

AK = 640
Δ ABC and ΔFJK are similar. They are small triangles.
ΔCDF is the big triangle.

640 / 2 = 320 m= CF
AC & FK= 320/2 = 160 m each

2AC = CF = 2FK
2(160) = 320 = 2(160)

BG = 20 m

20/160 = x / 320
20*320 = 160x
6400 = 160x
6400/160 = x
40 = x

Area of CDF = (40 m * 320 m)/2 = 12,800 / 2= 6,400 m²

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2 years ago

Find the surface area of the part of the sphere x2+y2+z2=81 that lies above the cone z=x2+y2−−−−−−√

TiliK225 [7]

Parameterize the part of the sphere by

$\mathbf s(u,v)=(9\cos u\sin v,9\sin u\sin v,9\cos v)$

with $0\le u\le2\pi$ and $0\le v\le\dfrac\pi4$ . Then

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=81\sin v\,\mathrm du\,\mathrm dv$

So the area of $S$ (the part of the sphere above the cone) is given by

$\displaystyle\iint_S\mathrm dS=81\int_{v=0}^{v=\pi/4}\int_{u=0}^{u=2\pi}\sin v\,\mathrm du\,\mathrm dv=81(2\pi)\left(1-\dfrac1{\sqrt2}\right)=(162-81\sqrt2)\pi$

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3 years ago

Helppp???<br> Last one has no answers to it

kotykmax [81]

Answer:

Exterior angle: <6

Step-by-step explanation:

Exterior angles are the angles outside.

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3 years ago

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