Can anyone pls ans this with clear steps

The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic

Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 10

r = number of success

p = probability of success which in our question is % of first-round

appeals that were successful, i.e.; 40%

So, here X ~ $Binom(n=10,p=0.40)$

(a) Probability that none of the appeals will be successful = P(X = 0)

P(X = 0) = $\binom{10}{0}0.40^{0}(1-0.40)^{10-0}$

= $1*0.6^{10}$ = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

P(X = 1) = $\binom{10}{1}0.40^{1}(1-0.40)^{10-1}$

= $10*0.4^{1} *0.6^{10-1}$ = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

P(X >= 2) = 1 - P(X = 0) - P(X = 1)

= 1 - $\binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}$

= 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful = P(X > 0.5)

For this probability we will convert our distribution into normal such that;

X ~ N( $\mu = n*p=4,\sigma^{2}= n*p*q = 2.4$ )

and standard normal z has distribution as;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

P(X > 0.5) = P( $\frac{X-\mu}{\sigma}$ > $\frac{0.5-4}{\sqrt{2.4} }$ ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0

3 years ago

A cube has a side length of 13 millimeters.What is the surface area of the cube?

wel

Surface area of a cube is n^2, n being the measurment of any one side of the cube. In this case, 13x13=169, so the answer is 169 mL^2.

8 0

3 years ago

Please help

mafiozo [28]

Answer:

Easy it's a right hand child

Step-by-step explanation:

Because if both husband and wife both have right hands. And it's 10% chance the child will be left handed. Then it's possible that the child is going to be a right hand.

4 0

3 years ago

Donatello Co. has identified an activity cost pool to which it has allocated estimated overhead of $9,600,000. It has determined

ahrayia [7]

Answer:

option (a) Widgets $2,400,000, Gadgets $1,800,000, Targets $5,400,000

Step-by-step explanation:

Data provided in the question:

Allocated estimated overhead = $9,600,000

Expected use of cost drivers for the activity = 800,000 inspections.

Inspections required by Widgets = 200,000

Inspections required by Gadgets = 150,000

Inspections required by Targets = 450,000

Therefore,

Total overhead per activity = $\frac{\textup{estimated overhead}}{\textup{Total activity}}$

= $\frac{\textup{9,600,000}}{\textup{800,000 }}$

= $12 per activity

Thus,

Overhead allocated to Widgets = 200,000 × 12 = $2,400,000

Overhead allocated to Gadgets = 150,000 × 12 = $1,800,000

Overhead allocated to Target = 450,000 × 12 = $5,400,000

Hence, The correct answer is option (a)

8 0

2 years ago

Help pls and thank you

photoshop1234 [79]

DONT CLICK THE LINK ITS A VIRUS

3 0

3 years ago

Can anyone pls ans this with clear steps​

Can anyone pls ans this with clear steps