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3 years ago

"It was you who awoke me last summer out of a life-long stupid dream" write the conclusion for this quote

1 answer:

4 0

The person that "awoke [the author]" helped change the authors life around and helped him find the purpose for his life

hope this helps

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PLEASE HELP

andre [41]

I believe that the answer for this is that she is going over budget considering that 100$ in debt she won't be able to pay because without the debt she would have to pay 1,605 out of her 1,700 so add 100 to 1,605 and she would be over budget

3 0

3 years ago

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Please answer this correctly

Aloiza [94]

Answer:

Height of this missing bar would be 1

Step-by-step explanation:

Since there is 1 and only 1 quantity between 80-99.

5 0

3 years ago

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Ben earns $9 per hour and $6 for each delivery he makes. He wants to make $155 in an 8-hour workday. What is the least number of

ioda

Find how much he will earn
we know he will earn 8 hours sofirst find how many he earns
9 per hour
8 hou
9*8=72
72+6*numberofdeliveries=155
minus 72
6*numberofdeliviers=83
divide by 6
number of delevieries=13.8
he can't make 13.8, round up to get 14

answer is 14 deliveries

7 0

3 years ago

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Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

3 years ago

The value of which of these expressions is closest to e?

Anna [14]

Answer:

Using a calculator, we can check that e=2.718281828.

Step-by-step explanation:

Lets evaluate each one of our expression the check which one is closest to e:

(1+ \frac{1}{31} )^{31}=2.675686306

(1+ \frac{1}{32})^{32}=2.676990129

(1+ \frac{1}{34} )^{34}=2.679355428

(1+ \frac{1}{33} )^{33}=2.678207651

We can conclude that the value of (1 +1/34) to the power of 34 is the closest to the value of e.

4 0

3 years ago

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