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3 years ago

Find the inverse of the function.

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

3 0

1/2 y +6 = x
y=2 (x-6)
= 2x-12
f^-1 (x)= 2x-12

Igoryamba3 years ago

3 0

Hello :
f(x) = 1/2 x +6
find : x
1/2x = f(x) -6
x = 2f(x) -12
the inverse is : f^-1 (x) = 2x-12

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Someone help pls :((

harina [27]

Answer:

56.714°

Step-by-step explanation:

Since we do not have a full angle of this proposed triangle, we must do this by splitting it into two right triangles instead of using the law of sines.

250m*sin(40°) = 250m*0.64278760968 = 160.696902422m

452.4m-160.696902422m=291.703097578m

Use pythagorean theorem:

$\sqrt{250^2 - 160.696902422^2}$

62500-25823.494448025787=36676.505552

$\sqrt{36676.505551974216}$ = 191.511110779m

arctan(291.703097578m/191.511110779m)≈56.714°

6 0

3 years ago

What is the answer to j/4-8<4

xeze [42]

To solve the above inequality we will try to isolate j by using the opposite operation of a number that we want to remove. So,

$\frac{j}{4}-8$

$\frac{j}{4} -8+8$ Add 8 to each sides.

$\frac{j}{4}$ By combining the like terms.

$\frac{j}{4}*4$ Multiply each sides by 4 to isolate j.

j<48 By simplifying.

So, the answer is j<48.

7 0

2 years ago

How many times larger is the value 250,000 then 250

Olegator [25]

1,000 (it needs 20 characters)...

4 0

2 years ago

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For what values of q are the two vectors A = i + j + kq each other and B-iq-23 + 2kg perpendicular to

Sloan [31]

Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors $A=i+j+kq$ and $B=iq-2j+2kq$ are perpendicular to each other.

To find : The value of q ?

Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. $\vec{A}\cdot \vec{B}=0$

Two vectors $A=i+j+kq$ and $B=iq-2j+2kq$

$(i+j+kq)\cdot (iq-2j+2kq)=0$

$(1)(q)+(1)(-2)+(q)(2q)=0$

$q-2+2q^2=0$

$2q^2+q-2=0$

Using quadratic formula,

$q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}$

$q=\frac{-1\pm\sqrt{17}}{4}$

$q=\frac{-1+\sqrt{17}}{4},\frac{-1-\sqrt{17}}{4}$

$q=0.781,-1.281$

Therefore, The value of q are 0.781,-1.281.

6 0

2 years ago

If an object is projected upward with an initial velocity of 129 ft per sec, its height h after t seconds is h = -16^2+123t. Fin

elena-s [515]

This problem can be solved directly by neglecting the initial velocity given. All we have to do is to plug in t = 4 in the given equation. That is:

h = -16^2 + 123 * 4

h = 236 ft

3 0

3 years ago

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