25 POINTS!!!!!!

Mathematics

1 answer:

motikmotik3 years ago

8 0

A =8000(1-.11)^5
The answer is D.
This is an exponential decay problem

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Find all the points having an x-coordinate of 4 whose distance from the point (-2,-1) is 10

Marta_Voda [28]

$A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\the\ distance\ between\ A\ and\ B:\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\A(-2;-1);\ B(4;\ y);\ d=10\\\\subtitute\\\\\sqrt{(4-(-2))^2+(y-(-1))^2}=10\\\\\sqrt{(4+2)^2+(y+1)^2}=10\\\\\sqrt{6^2+(y+1)^2}=10\\\\\sqrt{36+(y+1)^2}=10\ \ \ |square\ both\ sides\\\\36+(y+1)^2=10^2\\\\36+(y+1)^2=100\ \ \ |subtract\ 36\ from\ both\ sides\\\\(y+1)^2=64\iff y+1=-\sqrt{64}\ or\ y+1=\sqrt{64}\\\\y+1=-8\ or\ y+1=8\ \ \ \ |subtract\ 1\ from\ both\ sides\\\\y=-9\ or\ y=7$

$Answer:{\boxed{(4;-9)\ or\ (4;\ 7)}$

4 0

3 years ago

Need help asap this is due in 20 min!!! i will gove brainliest too! questions 8-11

andreev551 [17]

8. x= 7

9. x= 9

10. x= -10

11. x= -18

7 0

3 years ago

Tara had 1 5/8 pounds of dried nuts. She ate 1/4 pound of dried nuts each day for 6 days? How many pounds of dried nuts did Tara

Shalnov [3]

Answer:

1/8

Step-by-step explanation:

its easy just count backwards by 2/8 each time

8 0

3 years ago

Writing to explain. You are allowed. To spend. $125. For new. Clothes. You find a sweater that costs. $29.99, a jacket that cost

goblinko [34]

Add the cost of your sweater, cost of your jacket and cost of your socks together. Then subtract that from $125. Then whatever your answer is divide that by $22.50 and you will find out how many pairs of shoes you can buy.

4 0

3 years ago

Read 2 more answers

Which statement about the reflection below is true?

Pepsi [2]

Answer:

The distance between C and P is equal to the distance between C’ and P

Step-by-step explanation:

From the description, the diagram is similar to the one in the attachment.

To answer this question, we that the corresponding vertices of a polygon after a reflection are all equidistant from the line of reflection.

From the diagram, the red dotted line joining C and C', meet on the line of reflectionat P.

This implies that |CP|=|C'P'|.