Find the area of the parallelogram with vertices: (2,2,0),(5,3,0),(4,7,0),and(7,8,0).
PtichkaEL [24]
Answer:
13 square units
Step-by-step explanation:
Let the vertices of parallelogram are
A(2,2,0),B(5,3,0),C(4,7,0) and D(7,8,0)
Side AB=
Side AD=D-A=
We know that
Area of parallelogram=Magnitude of product of adjacent sides




Where x=Component along x-axis
y=Component along y- axis
z=Component along z-axis
Square units
Hence, the area of parallelogram=13 square units
Answer:
x = -1 or x = 7
Step-by-step explanation:
From my understanding, y will be zero and you have to find the value of x.
Step 1: Middle term break
y = x² + 6x - 7
x² + 6x - 7 = 0
x² - 7x + x - 7 = 0
Step 2: Solve
x(x-7) + 1(x-7) = 0
(x+1) (x-7) = 0
x = -1 or x = 7
Therefore, the value of x is either -1 or 7.
!!
Answer:
z = -9
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Terms/Coefficients/Degrees
Step-by-step explanation:
<u>Step 1: Define</u>
-21 = z - (-6 - 2z)
<u>Step 2: Solve for </u><u><em>z</em></u>
- Distribute negative: -21 = z + 6 + 2z
- Combine like terms: -21 = 3z + 6
- Isolate <em>z</em> term: -27 = 3z
- Isolate <em>z</em>: -9 = z
- Rewrite: z = -9
Well the median is the middle number, so I would say whenever the mean is lower than the median