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jolli1 [7]
3 years ago
12

Use Use an element argument to prove the state (A-B)U(ANB) = A" is true. he statement "For all sets A and B,

Mathematics
2 answers:
lys-0071 [83]3 years ago
3 0

Answer with Step-by-step explanation:

We have to prove that

(A-B)\cup (A\cap B)=A is true for all sets A and B

Let x\in(A-B)\cup (A\cap B)

Then x\in(A-B) or x\in(A\cap B)

x\in A and x\notin B or x\in A\;and\; x\in B

Hence, x\in A

Conversely ,Let x\in A

Then x belongs to A and x does not belongs to B then

x belongs to A- B

Or  x belongs to A and x belongs to B then x belongs to A \cap B

Hence, x\in( A-B)\cup (A\cap B)

Therefore, (A-B)\cup (A\cap B)=A

ozzi3 years ago
3 0

Answer with explanation:

To Prove: (A -B) ∪ (A ∩ B)=A

Proof:

Consider two sets A and B

⇒⇒ To prove A=B, in sets

We need to prove

A ⊆ B

and , B ⊆ A

then , A=B.

→A - B ⊆ A and A ∩ B ⊆ A

So, there are two possibilities

Either,→A⊆ A-B ∪ (A ∩ B) --------(1)

Or,→ A -B ∪ (A ∩ B)⊆ A-----------(2)

Combining (1) and (2) , we get

(A -B) ∪ (A ∩ B)=A

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A box has a volume of 192 cubic inches, a length that is twice as long as its width, and a height that is 2 inches greater than
Volgvan

Answer:

Length = 8 inches

Width = 4 inches

Height = 6 inches

Step-by-step explanation:

Volume of the box = 192 cubic inches

Volume of a box = length × width × height

Let

Width = x

Length = 2x

Height = x + 2

Volume of a box = length × width × height

192 = 2x * x * (x + 2)

192 = 2x^2 (x + 2)

192 = 2x^3 + 4x^2

Divide through by 2

96 = x^3 + 2x^2

Subtract 96 from both sides

x ^3 + 2x^2 - 96 = 0

Factorise

(x - 4) (x^2 + 6x + 24) = 0

x^2 + 6x + 24 has no real x-value

So,

Divide both sides by (x^2 + 6x + 24).

0 ÷ (x^2 + 6x + 24) = 0

So,

(x - 4) = 0

x = 4

Width = x = 4 inches

Length = 2x

= 2(4)

= 8 inches

Height = x + 2

= 4 + 2

= 6 inches

Check:

Volume of a box = length × width × height

= (8 * 4 * 6) inches

= 192 inches

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