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jolli1 [7]
3 years ago
12

Use Use an element argument to prove the state (A-B)U(ANB) = A" is true. he statement "For all sets A and B,

Mathematics
2 answers:
lys-0071 [83]3 years ago
3 0

Answer with Step-by-step explanation:

We have to prove that

(A-B)\cup (A\cap B)=A is true for all sets A and B

Let x\in(A-B)\cup (A\cap B)

Then x\in(A-B) or x\in(A\cap B)

x\in A and x\notin B or x\in A\;and\; x\in B

Hence, x\in A

Conversely ,Let x\in A

Then x belongs to A and x does not belongs to B then

x belongs to A- B

Or  x belongs to A and x belongs to B then x belongs to A \cap B

Hence, x\in( A-B)\cup (A\cap B)

Therefore, (A-B)\cup (A\cap B)=A

ozzi3 years ago
3 0

Answer with explanation:

To Prove: (A -B) ∪ (A ∩ B)=A

Proof:

Consider two sets A and B

⇒⇒ To prove A=B, in sets

We need to prove

A ⊆ B

and , B ⊆ A

then , A=B.

→A - B ⊆ A and A ∩ B ⊆ A

So, there are two possibilities

Either,→A⊆ A-B ∪ (A ∩ B) --------(1)

Or,→ A -B ∪ (A ∩ B)⊆ A-----------(2)

Combining (1) and (2) , we get

(A -B) ∪ (A ∩ B)=A

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Some of the children at a school arrive by car.
scZoUnD [109]

Answer:

  • <u>74%</u>

Explanation:

You can build a two-way relative frequency table to represent the data:

These are the columns and rows:

               Car         No car      Total

Boys

Girl

Total

Fill the table

  • <em>30% of the children at the school are boys</em>

             Car         No car      Total

Boys                                       30%

Girl

Total

  • <em>60% of the boys at the school arrive by car</em>

That is 60% of 30% = 0.6 × 30% = 18%

             Car         No car      Total

Boys      18%                         30%

Girls

Total

By difference you can fill the cell of Boy and No car: 30% - 18% = 12%

             Car         No car      Total

Boy       18%           12%         30%

Girl

Total

Also, you know that the grand total is 100%

             Car         No car      Total

Boy       18%           12%         30%

Girl

Total                                     100%

By difference you fill the total of Girls: 100% - 30% = 70%

             Car         No car      Total

Boy       18%           12%         30%

Girl                                         70%

Total                                     100%

  • <em>80% of the girls at the school arrive by car</em>

That is 80% of  70% = 0.8 × 70% = 56%

             Car         No car      Total

Boy       18%           12%         30%

Girl       56%                         70%

Total                                     100%

Now you can finish filling in the whole table calculating the differences:

             Car         No car      Total

Boy       18%           12%         30%

Girl        56%         14%         70%

Total     74%          26%      100%

Having the table completed you can find any relevant probability.

The probability that a child chosen at random from the school arrives by car is the total of the column Car: 74%.

That is because that column represents the percent of boys and girls that that  arrive by car: 18% of the boys, 56% of the girls, and 74% of all the the children.

8 0
3 years ago
Find the least common denominator of the fractions 5/12 and 2/5.
Gemiola [76]
The LCD (least common denominator) is the lowest number that both denominators (12 and 5) go into. The lowest number that both 5 and 12 go into is 60. The LCD of the two fractions is 60.
6 0
3 years ago
Read 2 more answers
Need help to solve please??<br> Need to proof
inysia [295]

Answer:

Step-by-step explanation:

#   Statement   Reasoning

1). KJ║ML    Given

2). ∠KLM ≅ ∠LKJ   Alternate interior angles

3). KL ≅ LK  Reflexive property

4). ΔKJL ≅ ΔLMK  SAS congruence postulate

8 0
3 years ago
A landscaper will install a sprinkler system for a client and has shown on a coordinate grid the location of the main water line
Fed [463]

Answer:

3rd option

Step-by-step explanation:

4 0
4 years ago
Una recta que pasa por los puntos A (2,1) y B (6,3) y otra recta pasa por A y por el punto (0,y) ¿Cuánto vale y, si ambas rectas
ASHA 777 [7]

The translation of the question given is

A line that passes through the points A (2,1) and B (6,3) and another line passes through A and through the point (0, y). What is y worth, if both lines are perpendicular?

Answer:

y = 5

Step-by-step explanation:

Line 1 that passes through A (2,1) and B (6,3)  

Slope (m1) = 3-1/6-2 = 2/4 = 1/2

y - 1 = \frac{1}{2} ( x -2)

2y - 2 = x- 2

y = \frac{x}{2}

Line 2 passes through A (2,1) and (0,y)

slope (m2) =\frac{y-1}{-2}

Line 1 and Line 2  are perpendicular

m1*m2 = -1

\frac{1}{2}  * \frac{y-1}{-2} = -1

y-1 = 4

y = 5

slope = -2

Equation of Line 2

Y-1 = -2(x-2)

y -1 = -2x +4

2x +y = 5

7 0
3 years ago
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