I drew it out. Hope this helps.
Answer: 2.093
Step-by-step explanation:
As per give , we have
Sample size : n= 20
Degree of freedom : df= n-1=19
Significance level : 
Since , the sample size is small (n<30) so we use t-test.
For confidence interval , we find two-tailed test value.
Using students's t-critical value table,
Critical t-value : 
Thus, the critical value for the 95% confidence interval = 2.093
Answer: B 5+5=10+4+4+4=12+3 10+12+3 25 lol
Step-by-step explanation:
You can use
Sine25=9/c
Or
Sin25/9=sine 90/c