Question

If x = 3y^4 and y = s/ 2x^3, show that s = 54y^13.

Answer 1

Answer:

see explanation

Step-by-step explanation:

Given

y = $\frac{s}{2x^3}$ ← multiply both sides by 2x³

2x³y = s ← substitute x = 3$y^{4}$ into left side, then

2$(3y^4)^{3}$ y = s, thus

s = 2 × 3³ × $y^{12}$ y

  = 2 × 27 × $y^{(12+1)}$

  = 54$y^{13}$