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olya-2409 [2.1K]
3 years ago
8

The taxes on a house valued at $60,000 are $450.00. The tax ratio is 16%.

Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0

Answer: $562.5

Step-by-step explanation:

Given : The taxes on a house valued at $60,000 are $450.00.

i.e. Market value of house = $60,000

Tax amount paid on $60,000 market value house = $450.00

Tax rate = (Tax amount on ) ÷ (Market value of house)

⇒ Tax rate=  0.0075

Market value of another house = $75,000

Tax amount paid on $75,000 market value house = (Tax rate) x ( (Market value of house))

= (0.0075 )x ( $75,000) = $562.5

Hence, the taxes on the house next door with a market value of $75,000= $562.5

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2x^(10)y^(12)

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A car travels 14km in 25mins . Find out how far the car can travel in 5 hours if the speed remains the same ? ​
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<h3><u>Answer :- </u></h3>

168 km ...

<h3><u>Explanation :- </u></h3>

It is given that the car travels 14km in 25 minutes..

Now , assume that the distance the car travel in 5 hours be x..

  • Since 1 hour = 60 minutes..
  • 5 hours = 300 minutes ..

• Thus , The two given statements are :-

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  • And, x km -------------> 300 minutes..

<h3><u>We know that , </u></h3>

  • The distance travelled by car and the time taken by the car is directly proportional to each other....

<h3>So , </h3>

\frac{14}{25}  =  \frac{x}{300}

= x = 168km

• Hence , Car can travel 168km in 5 hours ..

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6 0
2 years ago
Last year, ginger cost $15 per kilogram. Due to a harvest shortage this year, the price of ginger has to increase by 15% per kil
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<h3>Answer:    17.25 dollars</h3>

=======================================================

Explanation:

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The cost has increased by $2.25 which means the cost per kilogram is now 15+2.25 = 17.25 dollars

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As a slight shortcut, we can multiply the old cost (15) by the multiplier 1.15 to get the same result:

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This method allows us to chain together many percentage increases, and it also allows us to include percentage decreases as well. Note how 1.15 is basically the result of 100% + 15% = 1.00+0.15 = 1.15

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Determine the range of the function graphed above

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