Answer:
176 yards per minuye
Step-by-step explanation:
The answer is 69.27272727
(a) True. Suppose A is a not a square matrix, with m rows and n columns. Then A² is not defined, because you can't multiply an m×n matrix by another m×n matrix.
(b) False. As an example, consider the matrices


Then both AB and BA are defined, with


In general, you can multiply any m×n by any n×m matrix.
(c) True. Multiplying a m×n matrix by a n×m matrix always yields a m×m matrix, and multiplying a n×m matrix by a m×n matrix always yields a n×n matrix.
So for this function we will be using the quadratic formula, which is
, to solve. a = x^2 coefficient, b = x coefficient, and c = constant. Using our equation, we can solve for the zeros (x-intercepts) as such:

In short, your x-intercepts (rounded to the hundredths) are (1.92,0) and (-3.92,0).
Answer:
(x + 3, y - 2)
Step-by-step explanation:
we know that
The rule of the transformation T is equal to
T: pre-image → image
T: (x, y) → (x',y')
T: (x, y) → (x - 3, y + 2)
so
x'=x-3 ----> x=x'+3
y'=y+2 ----> y=y'-2
The rule of the inverse of transformation T -1 is equal to
T-1: image → pre-image
T-1: (x', y') → (x,y)
T-1: (x', y') → (x'+3, y'-2)