Question

Chapter 21, Problem 43Partially correct answer. Your answer is partially correct. Try again.The 1400-turn coil in a dc motor has an area per turn of 1.1 × 10-2 m2. The design for the motor specifies that the magnitude of the maximum torque is 8.4 N·m when the coil is placed in a 0.18-T magnetic field. What is the current in the coil?

Answer 1

Answer:

I = 3.028 A

Explanation:

given,

Number of turns in the coil = N = 1400

Area of DC motor per turn = 1.1 × 10⁻² m²

Maximum torque in motor = 8.4 N.m

Magnetic field in the coil = 0.18 T

Current in the coil = ?

using formula for toque in the magnetic field

   τ = N A B I

   8.4 = 1400 x 1.1 × 10⁻²  x 0.18 x I

   $I = \dfrac{8.4}{2.774}$

         I = 3.028 A

Current in the coil will be equal to I = 3.028 A