Answer:
Explanation:
Neglecting kinetic and potential energy effects, determine for the steam exiting the tank: (a) the mass flow rate, in kg/s. (b) the temperature, in °C.
The solution is shown in the picture below
The correct choice is :
The final momentum of the bullet/block is equal to the initial momentum of the bullet.
initially the block was at rest , hence
initial momentum of the block = 0
so total initial momentum was simply equal to initial momentum of bullet only.
after collision , the bullet gets embedded in the block , and hence both block-bullet move together at common velocity . according to conservation of momentum , momentum remains conserved in any type of collision.
so final momentum of bullet-block system = initial momentum of bullet
Answer:
3.42 cubic mm
Explanation:
Let density of fresh water be
And atmospheric pressure at the water surface be
Let g = 9.8 m/s2. The pressure at the dept of h = 25 m is
Using ideal gas law and assume constant temperature, we have the following equation to calculate the volume at the water surface , knowing that the volume at the lower depth V = 1 mm3:
Answer:
h = 12.8 cm
Explanation:
from the equation we are given the following:
distance = 6.4 cm
- when the object is being lowered the weight is equal to the spring force
weight = spring force
mg = ky ... equation 1
- potential energy to stretch a spring = work done by the spring
mgh = 0.5 x k x h^{2} ....equation 2
- substituting equation 1 into equation 2
kyh = 0.5 x k x h^{2}
y = 0.5 x h
2y = h
- where y = 6.4 , the maximum elonf=gation becomes
h = 2 x 6.4 = 12.8 cm