Answer:
a) F₁₂₀ = 1.34 pa A , b) F₂₀ = 0.746 pa A
Explanation:
Part. A
. The definition of pressure is
P = F / A
As the air can approach an ideal gas we can use the ideal gas equation
P V = n R T
Let's write this equation for two temperatures
P₁ V = n R T₁
P₂2 V = n R T₂
P₁ / P₂ = T₁ / T₂
point 1 has a pressure of P₁ = pa and a temperature of (20 + 273) K, point 2 is at (120 + 273) K, we calculate the pressure P₂
P₂ = P₁ T₂ / T₁
P₂ = pa 393/293
P₂ = 1.34 pa
We calculate the strength
P₂ = F₁₂₀ / A
F₁₂₀ = 1.34 pa A
Part B
In this case the data is
Point 1 has a temperature of 393K and an atmospheric pressure (P₁ = pa), point 2 has a temperature of 293K, let's calculate its pressure
P₁ / P₂ = T₁ / T₂
P₂ = P₁ T₂ / T₁
P₂ = pa 293/393
P₂ = 0.746 pa
Let's calculate the force (F20), from this point
F₂₀ / A = 0.746 pa
F₂₀ = 0.746 pa A
Answer: To every action there is an equal and opposite reaction. So as the defensive player collides with the receiver it feels an equal and opposite impact also.
Newton Third law of Motion
Explanation:
Answer:
15 m/s
Explanation:
Given data
Initial velocity= 0m/s----------since the cart was at rest
Final velocity = 30m/s
time= 30 seconds
Required
the average speed
We know that the sum of the initial and final velocity is divided by 2 to find the average velocity
average velocity= 0+30/2
average velocity= 30/2
average velocity= 15 m/s
Hence the average velocity is 15 m/s
False because opposites attract. :)
During a period of accelerating from zero to 24 m/s, the average speed is 12 m/s.