Question

Verify the identity. cot^2x/ cscx-1 = 1+sinx/sinx

Answer 1

Cot²x /(cscx + 1) = (1 - sinx) /sinx

let's apply the identity cot²x = csc²x - 1:

(csc²x - 1) /(cscx + 1) = (1 - sinx) /sinx

(factoring csc²x - 1 as a difference of squares and then simplifying)

[(cscx + 1)(cscx - 1)] /(cscx + 1) = (1 - sinx) /sinx

cscx - 1 = (1 - sinx) /sinx

let's recall that cscx = 1 /sinx:

(1 /sinx) - 1 = (1 - sinx) /sinx

ending with:


(1 - sinx) /sinx = (1 - sinx) /sinx (verified)


I hope it helps