Two consecutive integers do the the square root 45 lies

Mathematics

2 answers:

Zarrin [17]2 years ago

7 0

Answer:

square root 45 lies between 6 and 7

Step-by-step explanation:

I hope it's helpful!

horrorfan [7]2 years ago

6 0

Answer:

6 and 7

Step-by-step explanation:

Consider the perfect squares on either side of 45, that is

36 < 45 < 49 , then

$\sqrt{36}$ < $\sqrt{45}$ < $\sqrt{49}$ , that is

6 < $\sqrt{45}$ < 7

You might be interested in

The center of a circle lies on the line y = 4x + 1 and is tangent to the x-axis at (−3,0) . What is the equation of the circle i

Hunter-Best [27]

Answer:

$(x+3)^2+(y+11)^2=121$

Step-by-step explanation:

Consider a sketch of the problem as shown in the picture, where:

Blue line is given by y = 4x + 1.
Point B is the center of the circle.
Point A is (-3, 0).

Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.

So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.

Since the <em>general equation of the circle</em> of radius lenght r centered at (h, k) is given by

$(x-h)^2+(y-k)^2=r^2$