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adelina 88 [10]
3 years ago
9

Josiah had 1/5 + 1/2 he Sinister was 2/7

Mathematics
1 answer:
miskamm [114]3 years ago
5 0
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You might be interested in
The Powerball lottery is decided every Wednesday and Saturday night by drawing five white balls out of a drum with 69 balls and
Nadusha1986 [10]

Answer:

The question continues ; I take it is defined as a set of five white and one red number how many possible different Powerball tickets can be purchased how many possible different winning Powerball tickets are there

Step-by-step explanation:

he concept of combinatorics ( combination and permutation) is applied her

nPr = n!/(n-r)!

nCr = n!/(n-r)!r!

Hence number of possible different powerball tickets = number of ways of selection

= selecting 5 white ball from a total of 69 and selecting a red ball from a total of 26

= 69C5 x 26C1

using the formula above for combination

= 69!/(69-5)!5! x 26!/(26-1)!1!

= 292, 201, 338 ways

7 0
2 years ago
Pls help i am on a timer
storchak [24]

Answer:

I think the answer is C - (x+2)^2+1

6 0
3 years ago
There are three different hoses used to fill a pool: hose x, hose y, and hose z. Hose x can fill the pool in a days, hose y in b
WARRIOR [948]

Answer:

C) I and III only

Step-by-step explanation:

Let full pool is denoted by O

Days Hose x takes to fill pool O = a

Pool filled in one day x = O/a

Days Hose y takes to fill pool O = b

Pool filled in one day y = O/b

Days Hose z takes to fill pool O = c

Pool filled in one day z = O/c

It is given that

                         a>b>c

a>b>c>d\\\implies x

Days if if x+y+z fill the pool together = d

1 day if x+y+z fill the pool together =O(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=\frac{O}{d}---(1)

I) d < c

d are days when hose x, y, z are used together where as c are days when only z is used so number of days when three hoses are used together must be less than c when only z hose is used. So d < c

III) \frac{c}{3}

Using (1)

\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad(a>b>c)\\(ab+bc+ca)\frac{abc}{3ab}\\\\d>\frac{c}{3}

Similarly

\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad a>b>c\\(ab+bc+ca)>3bc\\\\d=\frac{abc}{ab+bc+ca}

So,

\frac{c}{3}

3 0
2 years ago
What is the value of x?<br> O 2 units<br> O 3 units<br> O 5 units<br> 08 units
Anna71 [15]

Answer:

The value of x is 5 units ⇒ C

Step-by-step explanation:

In the given figure

∵ Δ ABC is a right triangle at vertex B

∵ AC is its hypotenuse

∵ BD ⊥ AC

∴ (BD)² = AD × DC

∵ BD = 10 units

∵ AD = x units

∵ DC = 4x units

→ Substitute them in the rule above

∴ (10)² = x × 4x

∴ 100 = 4x²

→ Divide both sides by 4

∵ \frac{100}{4} = \frac{4x^{2}}{4}

∴ 25 = x²

→ Take √  for both sides

∴ 5 = x

∴ The value of x is 5 units

4 0
3 years ago
5x-7=5<br> How many solutions
krok68 [10]

Answer:

one solution

Step-by-step explanation:

5 0
2 years ago
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