<h3>
Answer: approximately 0.19 meters long</h3>
The more accurate value is 0.18982439916059 but this value isn't exact
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Explanation:
The volume of this rectangular block is 0.24*0.19*0.15 = 0.00684 cubic meters.
If we had a cube of this volume, then it has some side length x such that x^3 = 0.00684
Apply the cube root to both sides. This is the same as raising both sides to the 1/3 power
![x^3 = 0.00684\\\\x = \sqrt[3]{0.00684}\\\\x = (0.00684)^{1/3}\\\\x \approx 0.18982439916059\\\\x \approx 0.19\\\\](https://tex.z-dn.net/?f=x%5E3%20%3D%200.00684%5C%5C%5C%5Cx%20%3D%20%5Csqrt%5B3%5D%7B0.00684%7D%5C%5C%5C%5Cx%20%3D%20%280.00684%29%5E%7B1%2F3%7D%5C%5C%5C%5Cx%20%5Capprox%200.18982439916059%5C%5C%5C%5Cx%20%5Capprox%200.19%5C%5C%5C%5C)
The side length of the cube is approximately 0.19 meters long
Answer:
1/6
Step-by-step explanation:
1/2 ÷ 3 equation
1/2 ÷3/1 flip
1/2 x 1/3 multiply
1/6 Answer
Answer:
($2.123 ; $2.149)
Step-by-step explanation:
The prediction interval is expressed as :
Predicted value ± standard Error
Predicted value = $2.136
Standard Error = $0.013
Prediction interval :
Lower boundary = $2.136 - $0.013 = $2.123
Upper boundary = $2.136 + $0.013 = $2.149
($2.123 ; $2.149)
B.) The prediction interval provides a range for which the predicted value or price should fall Given a certain degree of probability. If the true value falls within this interval, then, our prediction would be deemed to have occurred not by chance.
Since the actual price within the predicted price interval, then I agree with the judge's Decison that the price was not artificially depressed.
The answer is n=10 I already did this
