Answer:
Step-by-step explanation:
Let's start with distributing: 
Simplify i with i in the second term, and rearrange.
. Since i in the denominator looks ugly, let's multiply top and bottom by i. 
. The middle passage is based on the fact that, by definition, 
Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
Answer:
I honeslty dont know I just need points to answer a question
Step-by-step explanation:
hope you find the answer youre looking for!
X2<span> - 25 = x</span>2<span> - 5</span>2<span> = (x - 5)(x + 5)
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