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3 years ago

Poetry can be found in everyday life, like in song lyrics. (Points : 10) a. True b. False

Mathematics

2 answers:

DanielleElmas [232]3 years ago

5 0

True because there are songs that have peotry

Dahasolnce [82]3 years ago

3 0

True because a song is like a poem

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I don’t have any questions just giving out some points(: have a good day

aleksandr82 [10.1K]

Answer:

yyaayayyaay

Step-by-step explanation:

6 0

2 years ago

Donna the trainer has two solo workout plans that she offers her clients: Plan A and Plan B. Each client does either one or the

kykrilka [37]

X=hours of plan A
y=hours of plan B

wed: 5x+6y=12
thu: 3x+2y=6

so
5x+6y=12 and
3x+2y=6
we can eliminate y's by multiplying 2nd equation by -3 and adding to first equation

-9x-6y=-18
<u>5x+6y=12 +</u>
-4x+0y=-6

-4x=-6
divid both sides by -4
x=-6/-4
x=3/2
x=1.5

sub back

3x+2y=6
3(1.5)+2y=6
4.5+2y=6
2y=1.5
y=0.75

Plan A=1.5 hours
Plan B=0.75 hours

3 0

2 years ago

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$

$xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}$

$xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}$

$xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)$

$\implies \boxed{xyz = x + y + z + 2}$

(C)

6 0

1 year ago

Maya spent her allowance on playing an arcade game a few times and riding the Ferris wheel more than once.

NISA [10]

Answer:

To write a two-variable equation, I would first need to know how much Maya’s allowance was. Then, I would need the cost of playing the arcade game and of riding the Ferris wheel. I could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. My variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation I could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

PERSEVERE Find the values of x and y,

Vlad [161]

y² = 8y - 15 (alternate angles are equal)

y² - 8y + 15 = 0

(y - 5)(y - 3) = 0

y = 5 or 3

x + 8y - 15 = 180 (angles in a straight line add up to 180)

when y = 5

x + 40 - 15 = 180

x = 155°

when y = 3

x + 24 - 15 = 180

x = 171°

8 0

2 years ago