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NISA [10]
2 years ago
13

A school administrator bought 6 desk sets. Each set consists of one table and one chair. He paid $48.50 for each chair. If he pa

id a total of $663 for the 6 sets, the cost of each table is
$
A;54.50
b;62.00
c;110.50
d;159.00
Mathematics
2 answers:
baherus [9]2 years ago
8 0
Total / amount of sets = price per set
Price per set - price for chair = cost of table

In numbers,
663/6 = 110.5
110.5-48.5 = 62

B is what I got
Pachacha [2.7K]2 years ago
8 0

Answer:

The answer is b

Step-by-step explanation: I did it on my calculator and don't know how to put it on here sorry but its b

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According to a polling​ organization, 24% of adults in a large region consider themselves to be liberal. A survey asked 200 resp
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Answer:

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Now we can calculate the p value based on the alternative hypothesis with this probability:

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Step-by-step explanation:

Information given

n=200 represent the random sample taken

X=75 represent the number of people Liberal

\hat p=\frac{75}{200}=0.375 estimated proportion of people liberal

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z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to verify if the true proportion of adults liberal is higher than 0.24:

Null hypothesis:p \leq 0.24  

Alternative hypothesis:p > 0.24  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.375 -0.24}{\sqrt{\frac{0.24(1-0.24)}{200}}}=4.47  

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The p value is very low compared to the significance level of \alpha=0.05 then we can reject the null hypothesis and we can conclude that the true proportion of people liberal is higher than 0.24

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